%s和%-s有什么区别啊。
如题

[解决办法]
-是指左对齐，在指定的宽度内，默认右对齐（Left-justify within the given field width; Right justification is the default）
%s和%-s没有指定宽度，二者没区别



[解决办法]
-, which specifies left adjustment of the converted argument in its field.
[解决办法]

C/C++ code

#include<stdio.h>#include<stdlib.h>int main(){    int i,j;    i=-78;    j=65535;        printf("%d%d\n",i,j);    printf("%4d%4d\n",i,j);    printf("%-4d%-4d\n",i,j);    printf("%+4d%+4d\n",i,j);     printf("%#x%#X\n",i,j);    printf("%04d%04d\n",i,j);    printf("% d% d\n",i,j);    system("pause");    return 0;}