下为一计算器程序 存在一问题 即无法实现第二次连加或连减，连乘和连除可以。求解。。
#include<stdio.h>
int main()
{
float a,c,e,result;
char b,d;
scanf("%f%c%f",&a,&b,&c);
result=a;
while(b!='#')
{
switch(b)
{
case '+':result=result+c;break;
case '-':result=result-c;break;
case '*':result=result*c;break;
case '/':result=result/c;break;
}
printf("the result is %f\n",result);
scanf("%c%f",&d,&e);
b=d;
c=e;
}

printf("the reult is %f\n",result);
return 0;
}


[解决办法]

C/C++ code

#include <stdio.h>#include <stdlib.h>int main(){    float a,c,e,result;    char b,d;    scanf("%f%c%f",&a,&b,&c);    fflush(stdin);    result=a;    while(b!='#')    {        switch(b)        {        case '+':result=result+c;break;        case '-':result=result-c;break;          case '*':result=result*c;break;          case '/':result=result/c;break;          }        printf("the result is %f\n",result);        scanf("%c%f",&d,&e);        fflush(stdin);        b=d;        c=e;    }    printf("the reult is %f\n",result);    system("pause");    return 0;}