scanf问题

C/C++ code

/* 求一串数字的和，以输入0为结束 */#include <stdio.h>#include <stdlib.h>main(){    int sum, number;        printf("This program sums a series of integers.\n");    printf("Enter integers (0 to terminate): ");        sum = 0;    while ((scanf("%d", &number)) != 0)        sum += number;    printf("The sum is : %d\n", sum);        system("PAUSE");    return 0;    }

编译后运行有问题
while ((scanf("%d", &number)) != 0)这句scanf这么用对么？scanf("%d", &number）是函数调用她返回的值是什么呢？


[解决办法]
不对。 scanf 函数的返回值是已赋值的域的各数，不是等于 d 的值。
比如说 scanf("%d%d%d", &number1，&number2，&number3))，如果number1,number2,number3都正确读入了，那么scanf 的返回值是3，不是其中某个number 变量的值
[解决办法]

C/C++ code

#include <stdio.h>#include <stdlib.h>int main(){    int sum, number;        printf("This program sums a series of integers.\n");    printf("Enter integers (0 to terminate): ");        sum = 0;    while ((scanf("%d", &number)) != 0)    {     if(number==0)         break;     sum += number;    }           printf("The sum is : %d\n", sum);        system("PAUSE");    return 0;    }
[解决办法]
scanf(）函数返回进入缓冲区的数据个数，比如说
scanf("%d",&number1）返回1
scanf("%d%d",&number1,&number2）返回2
scanf("%d%d%d",&number1,&number2&number3）返回3
当然如果类型不对，就返回0

[解决办法]
scanf的返回值表示正确读入的变量数量
出错返回0,遇到文件结束返回EOF.
[解决办法]
sum = 0;
   while ((scanf("%d", &number)) != 0)
   {
    if(number==0)
        break;
    sum += number;
   }

for (sum = 0; scanf("%d", &number)&&number; sum += number)
   ;