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sql server2000 里面怎么实现oracle10

发布时间: 2012-03-28 15:40:03 作者: rapoo

sql server2000 里面如何实现oracle10g的 wmsys.wm_concat 的功能?
sql server2000 里面如何实现oracle10g的 wmsys.wm_concat 的功能?

[解决办法]
wmsys.wm_concat 这个功能是干什么用的!
[解决办法]
行列转换是吧!
[解决办法]

SQL code
-------合并表-------/****************************************************************************************************************************************************** 合并分拆表数据 整理人:中国风(Roy) 日期:2008.06.06 ******************************************************************************************************************************************************/ --> --> (Roy)生成 if not object_id('Tab') is null     drop table Tab Go Create table Tab([Col1] int,[Col2] nvarchar(1)) Insert Tab select 1,N'a' union all select 1,N'b' union all select 1,N'c' union all select 2,N'd' union all select 2,N'e' union all select 3,N'f' Go 合并表: SQL2000用函数: go if object_id('F_Str') is not null     drop function F_Str go create function F_Str(@Col1 int) returns nvarchar(100) as begin     declare @S nvarchar(100)     select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1     return @S end go Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab go SQL2005用XML: 方法1: select     a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') from     (select distinct COl1 from Tab) a Cross apply     (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 方法2: select     a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) from     (select distinct COl1 from Tab) a cross apply     (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)                 .query(' <Tab>                 {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")}                 {concat("",string(/Tab[last()]/@COl2))}                 </Tab>')                 )b SQL05用CTE: ;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) ,Roy2 as (select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 union all select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1) select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0) 生成结果: /* Col1        COl2 ----------- ------------ 1          a,b,c 2          d,e 3          f (3 行受影响) */
[解决办法]
探讨
引用:
行列转换是吧!


恩,是的,在sqlserver里面如何用一句sql搞定呢?

[解决办法]
SQL code
if object_id('tb') is not null drop table tbcreate table tb(检验员  varchar(10), 打印日期 nvarchar(10),  漏检次数 int)goinsert tb select '罗邦卫','2009-7-31',2 insert tb select '梅强','2009-7-31',2 insert tb select '周林江','2009-7-31',1 insert tb select '周强','2009-7-31',3 insert tb select '陈刚','2009-8-1',1 insert tb select '陈华林','2009-8-1',2 insert tb select '董加军','2009-8-1',1 insert tb select '罗邦卫','2009-8-1',2 insert tb select '方文祥','2009-8-1',2 insert tb select '周林江','2009-8-1',2 insert tb select '周强','2009-8-1',1 insert tb select '陈刚','2009-8-3',1 insert tb select '陈华林','2009-8-3', 1 insert tb select '陈杰','2009-8-3',3 insert tb select '李林峰','2009-8-3',1 godeclare @sql nvarchar(4000)set @sql='select 检验员'   --变量必须初始化赋值select @sql=@sql+                 N','+quotename(打印日期)+                 N'=max(case 打印日期 when '+quotename(打印日期,N'''')+  --quotename(打印日期)=[打印日期],打印日期(打印日期,N'''')='2009-8-3'......                 N' then 漏检次数 else 0 end)'       from tb group by 打印日期  --按日期分组print @sqlexec(@sql+N' from tb group by 检验员')go检验员    2009-7-31    2009-8-1    2009-8-3陈刚    0    1    1陈华林    0    2    1陈杰    0    0    3董加军    0    1    0方文祥    0    2    0李林峰    0    0    1罗邦卫    2    2    0梅强    2    0    0周林江    1    2    0周强    3    1    0 


[解决办法]

SQL code
http://dev.yesky.com/394/2429894.shtml
[解决办法]
SQL code
----乌龟代码--- 
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)

1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb

/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc

(2 行受影响)
*/

--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go

select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id

/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc

(2 row(s) affected)

*/

drop table tb

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