很郁闷，关于style.display的问题
<input id=ipt1 NAME= "ipt1 "> <input id=ipt2 NAME= "ipt2 "> <input id=ipt3 NAME= "ipt3 ">

<input type=button onclick=doit() value=doit>
<script>
function doit()
{
ipt1.style.display = "none ";
ipt2.style.display = "none ";
ipt3.style.display = "none ";
ipt1.style.display = "block ";
ipt2.style.display = "block ";
ipt3.style.display = "block ";
}
</script>

本来是连着的3个input，一按就变不同行了，大家看看怎么解决.

[解决办法]
不知道你代码为了实现什么效果;

在display的取值中,block的说明如下:
------------------------------------------
block : 　CSS1　块对象的默认值。用该值为对象之后添加新行
[解决办法]
呵呵，早上才给同事看到个这问题，直接用id.style.display= " ";(显示)
id.style.display= "none ";(不显示)
[解决办法]
function doit() {
document.all.ipt1.style.display = document.all.ipt1.style.display!= "none "? "none ": " ";
document.all.ipt2.style.display = document.all.ipt2.style.display!= "none "? "none ": " ";
document.all.ipt3.style.display = document.all.ipt3.style.display!= "none "? "none ": " ";
}

[解决办法]
百度一下

网页制作完全手册
[解决办法]
JF
[解决办法]
<input id=ipt1 NAME= "ipt1 "> <input id=ipt2 NAME= "ipt2 "> <input id=ipt3 NAME= "ipt3 ">

<input type=button onclick=doit() value=doit>
<script>
function doit()
{
ipt1.style.display = " ";
ipt2.style.display = " ";
ipt3.style.display = " ";
ipt1.style.display = "block ";
ipt2.style.display = "block ";
ipt3.style.display = "block ";
}
</script>