通过位操作实现二进制的交叉结合
如题：
如三个二进制字符串：
X=x1 x2 x3..
Y=y1 y2 y3..
Z=z1 z2 z3..

说明:x1 x2 x3 y1 y2...z3..为0 or 1 二进制码

通过位操作，实现：
M=z1y1x1z2y2x2z3y3x3

例如：
X=101
Y=010
Z=111

则：M=101 110 101

[解决办法]

C/C++ code

int GetBitLen(short i){    short len;    short stemp;    stemp = i;    while( stemp && 0xFFFF)    {        len++;        stemp = stemp>>1;    }    return len;}int main(){     short a = 17;    short b = 21;    short c = 34;    short len = 0;    int temp = 0;    int M = 0;    len = GetBitLen(b);    if(GetBitLen(a)>GetBitLen(b))    {        len = GetBitLen(a);    }    if(len<GetBitLen(c))    {        len = GetBitLen(c);    }    M  = a&0x01 | (b&0x01)<<1 | (c&0x01)<< 2;    for(int i =1; i<len; i++)    {        a = a>>1;        b = b>>1;        c = c>>1;        temp = a&0x01 | (b&0x01)<<1 | (c&0x01)<< 2;        M = temp << (3*i) | M;    }    printf("%d\n",M);    getch();    return 0;}