查找json数据

JScript code

[    {"id": 123, "con": "gggdfg"},    {"id": 124, "con": "jgjjghj"},    {"id": 125, "con": "khkhk"},    {"id": 126, "con": "ggtyuryrty"},    {"id": 127, "con": "dfsfsf"}]

例如上面，我要查找id=125的con的内容应该怎么写啊

[解决办法]
遍历呀

JScript code

<script>d = [    {"id": 123, "con": "gggdfg"},    {"id": 124, "con": "jgjjghj"},    {"id": 125, "con": "khkhk"},    {"id": 126, "con": "ggtyuryrty"},    {"id": 127, "con": "dfsfsf"}];for(i=0; i<(d.length); i++)  if(d[i].id == 125) alert(d[i].con);</script>
[解决办法]
    function getCon(array){
       for(var i = 0;i<array.length;i++){
           var obj = array[i];
           if(obj.id == "125"){
               return obj.con;
           }
       }
       return null;
   }
   var array = [ {"id": 123, "con": "gggdfg"}, {"id": 124, "con": "jgjjghj"}, {"id": 125, "con": "khkhk"}, {"id": 126, "con": "ggtyuryrty"}, {"id": 127, "con": "dfsfsf"} ]
   var result = getCon(array);
   alert(result);
[解决办法]
JScript code
    var t2 = [    {"id": 123, "con": "gggdfg"},    {"id": 124, "con": "jgjjghj"},    {"id": 125, "con": "khkhk"},    {"id": 126, "con": "ggtyuryrty"},    {"id": 127, "con": "dfsfsf"}];var myobj=eval(t2);for(var i=0;i<myobj.length;i++){   alert(myobj[i].id);   alert(myobj[i].con);}
[解决办法]
如果你的结构就是这样的两个元素，而且每个ID都不重复，为了以后随时取用某个ID的CON，我建议可以加这个数据存储到一个关联数组中
  
JScript code
      var arr1 = [    { "id": 123, "con": "gggdfg" },    { "id": 124, "con": "jgjjghj" },    { "id": 125, "con": "khkhk" },    { "id": 126, "con": "ggtyuryrty" },    { "id": 127, "con": "dfsfsf" }];    var arr2 = new Array;    for (var i = 0; i < arr1.length; i++) {        arr2[arr1[i]["id"]] = arr1[i]["con"];    }    alert(arr2["125"]);