php错误：You have an error in your SQL syntax; 急！！！！！

$sql="select id,title,type_id,time from news limit $offset,$Page_size where type_id=".$type_id;
echo $sql;
$result=mysql_query($sql) or die($sql."<br/><br/>".mysql_error());;
while ($row=mysql_fetch_array($result))
{
?>
<tr>
<td bgcolor="#E0EEE0" height="25px"><div align="center">
<?php echo $row[1]?>
</div></td>
<td bgcolor="#E0EEE"><div align="center">
<?php echo $row[2]?>
</div></td>
<td bgcolor="#E0EEE"><div align="center">
<?php echo $row[3]?>
</div></td>
<td bgcolor="#E0EEE"><div align="center">
<a href="newsChange_ok.php?id=<?php echo $row[0] ?>">修改</a>   <a href="#">删除</a>
</div></td>
</tr>



直接上代码！！！！！错误提示：You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''0,6' where type_id=21' at line 1


请问怎么回事啊？？？？？？？？？？？？？？？？？？急！！！！！！！！！！！！！！！！！！

[解决办法]
select id,title,type_id,time from news limit $offset,$Page_size where type_id=".$type_id;

修改成

select id,title,type_id,time from news where type_id=".$type_id." ORDER BY ID DESC LIMIT {$offset},{$Page_size}";

看看.