C++里的数组作为参数怎么传递？
大家看如下一个冒泡排序，我写成一个函数，数组怎么传递呀？　我这样写有问题。

C/C++ code

#include <conio.h>#include <iostream.h>#pragma hdrstop//---------------------------------------#pragma argsused#define N 9                                    //定义数组元素个数int maopao(int A[]);int main(int argc, char* argv[]){    int A[9] = {19,23,79,33,13,68,99,36,28};    maopao( A[] );    return 0;}int maopao(int A[]){    int a[] = A[];    int i, j, temp;    cout << "排序前：";    for(i=0; i<N; i++)        cout << a[i] << " ";    for(i=0; i<N; i++)    {        for(j=i+1; j<N; j++)        {            if(a[i]>a[j])            {                temp = a[j];                a[j] = a[i];                a[i] = temp;            }        }    }    cout << "\n排序后：";    for(i=0; i<N; i++)        cout << a[i] << " ";    getch();    return 0;

[解决办法]
maopao( A );


int maopao(int *A)
{
int i, j, temp;
cout << "排序前：";
for(i=0; i<N; i++)
cout << A[i] << " ";
for(i=0; i<N; i++)
{
for(j=i+1; j<N; j++)
{
if(A[i]>A[j])
{
temp = a[j];
A[j] = A[i];
A[i] = temp;
}
}
}
cout << "\n排序后：";
for(i=0; i<N; i++)
cout << A[i] << " ";
getch();
return 0;

[解决办法]

C/C++ code

 
 #include  <conio.h> 
 #include  <iostream> 
 //#pragma hdrstop 
 using namespace std; 
  
 //--------------------------------------- 
  
 #pragma argsused 
 #define N 9   
                 //定义数组元素个数 
 void maopao(int A[]); 
 int main(int argc, char* argv[]) 
 { 
   int A[9] = {19,23,79,33,13,68,99,36,28}; 
   maopao(A);//调用的时候直接用数组名就可 
   getch(); 
   return 0; 
 } 
  
 void maopao(int A[]) 
 { 
   int *a;//此处用指针 
   a=A;//把数组的首地址赋给a,a就是一个数组了 
   int i, j, temp; 
   cout  < < "排序前："; 
   for(i=0; i <N; i++) 
     cout  < < a[i]  < < " "; 
   for(i=0; i <N; i++) 
   { 
     for(j=i+1; j <N; j++) 
     { 
       if(a[i]>a[j]) 
       { 
         temp = a[j]; 
         a[j] = a[i]; 
         a[i] = temp; 
       } 
     } 
   } 
   cout  < < "\n排序后："; 
   for(i=0; i <N; i++) 
     cout  < < a[i]  < < " "; 
    
 } 
 

[解决办法]
嗯 用指针就行了.
如果要传整个数组也是可以的,就是封装到struct中传但是效率有问题
[解决办法]

探讨

maopao( A );


int maopao(int *A)
{
int i, j, temp;
cout < < "排序前：";
for(i=0; i <N; i++)
cout < < A[i] < < " ";
for(i=0; i <N; i++)
{
for(j=i+1; j <N; j++)
{
if(A[i]>A[j])

{
temp = a[j];
A[j] = A[i];
A[i] = temp;
}
}
}
cout < < "\n排序后：";
for(i=0; i <N; i++)
cout < < A[i] < < " ";
getch();
return 0;

[解决办法]

C/C++ code

#include <conio.h>#include <iostream>using namespace std;//#pragma hdrstop//#pragma argsused#define N 9                                    //定义数组元素个数int maopao(int A[]);int main(int argc, char* argv[]){    int A[9] = {19,23,79,33,13,68,99,36,28};        maopao( A );        return 0;}//数组作为参数传递时，其实传递的就是指针。int maopao(int A[]){    int * a = A; //数组的首地址可以用指针来表示    int i, j, temp;    cout << "排序前：";    for(i=0; i<N; i++)        cout << a[i] << " ";    for(i=0; i<N; i++)    {        for(j=i+1; j<N; j++)        {            if(a[i]>a[j])            {                temp = a[j];                a[j] = a[i];                a[i] = temp;            }        }    }        cout << "\n排序后：";    for(i=0; i<N; i++)        cout << a[i] << " ";            getch();    return 0;}