至急 sed 如何取得第一个回车后的所有
现在有如下
update KHI4.ASOF_INFss set ASOF = current date-150 days,USERID = 'GKDP',TIMESTP = Current Timestamp
DB21034E The command was processed as an SQL statement because it was not a
valid Command Line Processor command. During SQL processing it returned:
SQL0204N "KHI4.ASOF_INFSS" is an undefined name. SQLSTATE=42704

我只想要
DB21034E The command was processed as an SQL statement because it was not a
valid Command Line Processor command. During SQL processing it returned:
SQL0204N "KHI4.ASOF_INFSS" is an undefined name. SQLSTATE=42704

是否能通过sed 截取第一个回车后的所有字段。

如果您有别的好的方法也可以。
谢谢了。

[解决办法]

BatchFile code

#! /bin/sh## file: skipline.sh# auth: mymtom# date: 2008-02-22#DATA=`cat <<EOFupdate KHI4.ASOF_INFss set ASOF = current date-150 days,USERID = 'GKDP',TIMESTP = Current TimestampDB21034E The command was processed as an SQL statement because it was not avalid Command Line Processor command. During SQL processing it returned:SQL0204N "KHI4.ASOF_INFSS" is an undefined name. SQLSTATE=42704EOF`echo "${DATA}"echo ""echo "${DATA}" | awk 'BEGIN {getline} 0==0 {print $0}'echo ""echo "${DATA}" | \awk -v n=$1 'BEGIN { for (i = 0; i < n; i++) {getline;} } \0==0 { printf("%s\n", $0); }'