一个棘手问题，大家帮我看看程序
#include "stdio.h "
main()
{ FILE *in,*out;
char ch,infile[10],outfile[10];
printf( " infile name:\n ");
scanf( " %s ",infile);
printf( "outfile name:\n ");
scanf( " %s ",outfile);
if ((in=fopen (infile, "rb "))==NULL)
{printf( "cant open infile\n ");
exit(0);
}
if ((out=fopen(outfile, "wb "))==NULL)
{printf( "cant open outfile\n ");
exit(0);
}
while(!feof(in))fputc (fgetc(in),out);
fclose(in);
fclose(out);
}
用上面这个程序，我把一个wav语音文件内容打开，并复制到txt中，但是看到的都是乱码，请问高手，有没有办法把二进制数显示出来，并保存。

[解决办法]
// 我们把每行输出结果分成3部分，本别处理，统一输出
// buf1 编号；buf2 数据； buf3 字符
// 将整理后的信息全部放到str中，供下面的程序使用
void data_format(char *str, unsigned char *buf, int len)
{
int i = 0;
int pos = 0;
char buf1[100] = {0};
char buf2[100] = {0};
char buf3[100] = {0};
char str0[2048] = {0};

while(pos < len)
{
pos++;

// 如果是ASCII字符
if (buf[0] > = 33 && buf[0] <= 126)
{
buf3[i] = buf[0];
}
else
{
buf3[i] = '. ';
}

i++;

sprintf(buf2, "%s%02X ", buf2, (unsigned char)buf[0]);

if(pos%16 == 0)
{
buf3[i] = 0;
i = 0;
sprintf((char *)buf1, "%09Xh: ", pos - 16);
sprintf(str0, "%-13s%-49s%-17s\n ", buf1, buf2, buf3);
strcat(str, str0);
buf2[0] = 0;
buf3[0] = 0;
}

buf++;
}
if (pos%16 != 0)
{
buf3[i] = 0;
sprintf((char *)buf1, "%09Xh: ", pos-pos%16);
sprintf(str0, "%-13s%-49s%-17s\n ", buf1, buf2, buf3);
strcat(str, str0);
}

return;
}

输出的样子如下：
000000000h: 00 12 79 D0 76 AB 00 08 7C ED DD 00 08 00 45 00 ..y.v...|.....E.
000000010h: 00 28 E5 BC 40 00 7F 06 CC 02 0A DC 02 52 0A DC .(..@........R..
000000020h: 32 07 08 8F 00 16 F5 3C 5E AB FF 66 51 3B 50 10 2...... <^..fQ;P.
000000030h: 3A F4 7D A0 00 00 00 00 00 00 00 00 :.}.........

[解决办法]
赞LS的，如果楼主要简单的话
#include "stdio.h "
void main()
{
FILE *in,*out;
char infile[100],outfile[100];
int i = 1;

printf( " infile name:\n ");
scanf( " %s ",infile);
printf( "outfile name:\n ");
scanf( " %s ",outfile);
if ((in=fopen (infile, "rb "))==NULL)
{
printf( "cant open infile\n ");
exit(0);
}
if ((out=fopen(outfile, "w "))==NULL)
{
printf( "cant open outfile\n ");
exit(0);
}
while(!feof(in))
{
fprintf(out, "0x%02x ", fgetc(in));
if ((i++) % 15 == 0)
fprintf(out, "\n ");
}
fclose(in);
fclose(out);
}