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一个SQL语句求解,该怎么解决

发布时间: 2012-04-10 21:03:56 作者: rapoo

一个SQL语句,求解
elect wcsj,SPSJ,ZGSPSJ,ZJLSPSJ,djbh
from IN_GZCLDH
where ZF='N'
and ZDRQ>='2012-1-1' and ZDRQ<='2012-1-31'
and ZJLSP='同意'
and case when WCSJ is not null then DATEDIFF(HOUR,ZJLSPSJ,WCSJ) else DATEDIFF(HOUR,ZJLSPSJ,GETDATE()) end>24



最后END>24代表什么意思,小弟求解

[解决办法]

SQL code
elect wcsj,SPSJ,ZGSPSJ,ZJLSPSJ,djbhfrom IN_GZCLDHwhere ZF='N'and ZDRQ>='2012-1-1' and ZDRQ<='2012-1-31'and ZJLSP='同意'and )case when WCSJ is not null then DATEDIFF(HOUR,ZJLSPSJ,WCSJ) else DATEDIFF(HOUR,ZJLSPSJ,GETDATE()) end)>24--加个括号你就能看懂了吧!也就是时间差的返回值大于24 

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