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求解!解决办法

发布时间: 2012-04-16 16:20:04 作者: rapoo

求解!!!!!!!!!!!
Keep on Truckin'
Problem Description:
Boudreaux and Thibodeaux are on the road again . . .
"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"
"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"
"We're not going to make it, I say!"
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?
Input :

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.
The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive

Output :

There will be exactly one line of output. This line will be:
NO CRASH
if the height of the 18-wheeler is less than the height of each of the underpasses, or:
CRASH X
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

Sample Input :
180 160 170

Sample Output
CRASH 160



[解决办法]

C/C++ code
#include<stdio.h>#include <iostream>using namespace std;int main(){    int a,b,c;    int T=168;    while(cin>>a>>b>>c)    {        if(T>=a){cout<<"CRASH "<<a<<endl;}        else if(T>=b){cout<<"CRASH "<<b<<endl;}        else if(T>=c){cout<<"CRASH "<<c<<endl;}        else{cout<<"NO CRASH"<<endl;}    }} 

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