php、Ajax、Post的传值的例子，运行有问题，帮忙看看！！！！！！
这是我在网上找到的一个例子，我运行时有问题，帮忙看看！http://cjmxp007.blog.163.com/blog/static/3547383720074252134287/
- JScript code
php Ajax Post 传值用Ajax 进行Post传值以下程序已调试通过：<head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>Untitled Document</title></head><script language="javascript">function saveUserInfo(){//获取接受返回信息层var msg = document.getElementById("msg");//获取表单对象和用户信息值var f = document.user_info;var userName = f.user_name.value;var userAge = f.user_age.value;var userSex = f.user_sex.value;//接收表单的URL地址var url = "/ajax_output.php";//需要POST的值，把每个变量都通过&来联接var postStr = "user_name="+ userName +"&user_age="+ userAge +"&user_sex="+ userSex;//实例化Ajax//var ajax = InitAjax(); var ajax = false; //开始初始化XMLHttpRequest对象 if(window.XMLHttpRequest) { //Mozilla 浏览器 ajax = new XMLHttpRequest(); if (ajax.overrideMimeType) {//设置MiME类别 ajax.overrideMimeType("text/xml"); } } else if (window.ActiveXObject) { // IE浏览器 try { ajax = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { ajax = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!ajax) { // 异常，创建对象实例失败 window.alert("不能创建XMLHttpRequest对象实例."); return false; } //通过Post方式打开连接ajax.open("POST", url, true);//定义传输的文件HTTP头信息ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded");//发送POST数据ajax.send(postStr);//获取执行状态ajax.onreadystatechange = function() { //如果执行状态成功，那么就把返回信息写到指定的层里 if (ajax.readyState == 4 && ajax.status == 200) { msg.innerHTML = ajax.responseText; } } }</script><body ><div id="msg"></div><form name="user_info" method="post" action="">姓名：<input type="text" name="user_name" /><br />年龄：<input type="text" name="user_age" /><br />性别：<input type="text" name="user_sex" /><br /><input type="button" value="提交表单" onClick="saveUserInfo()"></form></body>以上页面存为ajax.php然后再建 一个PHP文件，ajax_output.php<? echo $_POST['user_name']; echo $_POST['user_age']; echo $_POST['user_sex'];?>[解决办法]
这样试试：
- HTML code
<script language="javascript">function saveUserInfo(f){ var userName = f.user_name.value; var userAge = f.user_age.value; var userSex = f.user_sex.value; var url = "/ajax_output.php?"+new Date().getTime=
[解决办法]
ajax_output.php
- PHP code
<? if(empty($_POST['username'])){die('ajax failed!')} echo "ajax success!<br>"; echo $_POST['username']; echo $_POST['userage']; echo $_POST['usersex'];?>
[解决办法]
var url = "/ajax_output.php";
不用/吧，
var userName = f.user_name.value;
var userAge = f.user_age.value;
var userSex = f.user_sex.value;
取值尽量用documen.getElementById()；为每一个input加个id属性
if (ajax.readyState == 4){
if(ajax.status == 200) {
msg.innerHTML = ajax.responseText;
}
},我习惯分开写两个if，
具体什么错误LZ没说吧