C# 读取XML每个节点的值
XML文档结构如下：
<?xml version="1.0" encoding="utf-8"?>
<packet>
<proto name="1" showname="1">
<field name="1-1" showname="1-1" show="1-1"/>
<field name="1-2" showname="1-2" show="1-2"/>
<field name="1-3" showname="1-3" show="1-3"/>
<field name="1-4" showname="1-4" show="1-4"/>
</proto>
<proto name="2" showname="2">
<field name="2-1" showname="2-1" show="2-1"/>
<field name="2-2" showname="2-2" show="2-2"/>
<field name="2-3" showname="2-3" show="2-3"/>
<field name="2-4" showname="2-4" show="2-4"/>
<field name="2-5" showname="2-5" show="2-5"/>
<field name="2-6" showname="2-6" show="2-6"/>
<field name="2-7" showname="2-7" show="2-7"/>
<field name="2-8" showname="2-8" show="2-8"/>
</proto>
<proto name="3" showname="3">
<field name="3-1" showname="3-1" show="3-1">
<field name="3-1-1" showname="3-1-1" show="3-1-1"/>
<field name="3-1-2" showname="3-1-2" show="3-1-2"/>
<field name="3-1-3" showname="3-1-3" show="3-1-3"/>
</field>
<field name="3-2" showname="3-2" show="3-2">
<field name="3-2-1" showname="3-2-1" show="3-2-1"/>
<field name="3-2-2" showname="3-2-2" show="3-2-2"/>
<field name="3-2-3" showname="3-2-3" show="3-2-3"/>
</field>
</proto>
<proto name="4" showname="4">
<field name="4-1" value="4-1"/>
<field name="4-2" showname="4-2" show="4-2">
<file name="4-2-1" showname="4-2-1" show="4-2-1"/>
</field>
</proto>
</packet>
C#读取该XML每个节点的showname 和 show的值， 没有要读取value的值，我被循环弄混头脑，希望得到帮助...谢谢







[解决办法]

C# code

读：     //打开某文件(假设web.config在根目录中)    string filename=Server.MapPath("/") + @"WebApplication1\web.config";    XmlDocument xmldoc= new XmlDocument();    xmldoc.Load(filename);    //得到顶层节点列表    XmlNodeList topM=xmldoc.DocumentElement.ChildNodes;    foreach(XmlElement element in topM)    {     if(element.Name.ToLower()=="appsettings")     {      //得到该节点的子节点      XmlNodeList nodelist=element.ChildNodes;      if ( nodelist.Count >0 )      {       //DropDownList1.Items.Clear();       foreach(XmlElement el in nodelist)//读元素值       {        //DropDownList1.Items.Add(el.Attributes["key"].InnerXml);        //this.TextBox2.Text=el.Attributes["key"].InnerText;        this.TextBox2.Text=el.Attributes["key"].Value;        this.Label1.Text=el.Attributes["value"].Value;            //同样在这里可以修改元素值,在后面save。         // el.Attributes["value"].Value=this.TextBox2.Text;       }      }     }    }    xmldoc.Save(filename);   }效果：<appSettings>    <add key="密码" value="admin" />    <add key="ltp" value="first" /></appSettings>//添加空元素：   XmlNode node=doc.CreateElement(groupname);     node.InnerText="";     doc.LastChild.AppendChild(node);     doc.Save(xmlfile);删除一个节点元素   string itemname=this.listBox1.SelectedItem.ToString();      this.listBox1.Items.Remove(this.listBox1.SelectedItem);   //begin del xmlfile   XmlDocument doc=new XmlDocument();   doc.Load(xmlfile);      XmlNodeList topM=doc.DocumentElement.ChildNodes;   foreach(XmlElement element in topM)   {    if(element.Name==this.comboBox1.Text)    {     //得到该节点的子节点     XmlNodeList nodelist=element.ChildNodes;          foreach(XmlElement el in nodelist)//读元素值     {             if(el.Attributes["key"].Value==itemname)      {       element.RemoveChild(el);      }     }//循环元素          }//得到组   }//循环组   doc.Save(xmlfile); //一定要保存一下，否则不起作用//筛选数据private void Reader_Xml(string pathFlie){   XmlDocument Xmldoc=new XmlDocument();   Xmldoc.Load(pathFlie);   XmlNodeList Record1=Xmldoc.DocumentElement.SelectNodes(Code[@id='1'])   int f=0;   foreach(XmlNode xnode in Record1)    {    }} /**//*读取xml数据   两种xml方式*/<aaa>     <bb>something</bb>     <cc>something</cc></aaa><aaa>    <add key="123" value="321"/></aaa>/**//*第一种方法*/DS.ReadXml("your xmlfile name");Container.DataItem("bb");Container.DataItem("cc");DS.ReadXmlSchema("your xmlfile name");/**//*第二种方法*/<aaa>    <add key="123" value="321"/></aaa>如果我要找到123然后取到321应该怎么写呢？using System.XML;XmlDataDocument xmlDoc = new System.Xml.XmlDataDocument();xmlDoc.Load(@"c:\Config.xml");XmlElement elem = xmlDoc.GetElementById("add");string str = elem.Attributes["value"].Value/**//*第三种方法: SelectSingleNode 读取两种格式的xml *---/--------------------------------<?xml version="1.0" encoding="utf-8" ?><configuration>    <appSettings>       <ConnectionString>Data Source=yf; user id=ctm_dbo;password=123</ConnectionString>在某节点下增加一个元素，并设置值：    if(element.Name.ToLower()=="appsettings")    {     XmlElement elem =xmldoc.CreateElement("add");          element.AppendChild(elem);     elem.InnerText="ltp";     xmldoc.Save(filename);           }效果：<appSettings>    <add key="密码" value="admin" />    <add>ltp</add></appSettings>在某节点下增加一个元素，并增加两个属性：    if(element.Name.ToLower()=="appsettings")    {     XmlElement elem =xmldoc.CreateElement("add");     element.AppendChild(elem);     XmlAttribute xa=xmldoc.CreateAttribute("key");     xa.Value="ltp";     XmlAttribute xa2=xmldoc.CreateAttribute("value");     xa2.Value="first";     elem.SetAttributeNode(xa);     elem.SetAttributeNode(xa2);     xmldoc.Save(filename);</appSettings></configuration>--------------------------------------XmlDocument doc = new XmlDocument();doc.Load(strXmlName);    XmlNode node=doc.SelectSingleNode("/configuration/appSettings/ConnectionString");    if(node!=null)    {     string k1=node.Value;    //null     string k2=node.InnerText;//Data Source=yf; user id=ctm_dbo;password=123     string k3=node.InnerXml;//Data Source=yf; user id=ctm_dbo;password=123     node=null;    }********************************************************************<?xml version="1.0" encoding="utf-8" ?><configuration>    <appSettings>       <add key="ConnectionString" value="Data Source=yf; user id=ctm_dbo;password=123" />             </appSettings></configuration>**--------------------------------**     XmlNode node=doc.SelectSingleNode("/configuration/appSettings/add");    if(node!=null)    {     string k=node.Attributes["key"].Value;     string v=node.Attributes["value"].Value;     node=null;    }*--------------------------------*    XmlNode node=doc.SelectSingleNode("/configuration/appSettings/add");    if(node!=null)    {     XmlNodeReader nr=new XmlNodeReader(node);     nr.MoveToContent();    //检查当前节点是否是内容节点。如果此节点不是内容节点，则读取器向前跳至下一个内容节点或文件结尾。     nr.MoveToAttribute("value");     string s=nr.Value;     node=null;    } 
 
[解决办法]
http://blog.csdn.net/llwinnner/archive/2009/03/18/4002739.aspx
[解决办法]
咋又发了一次:
C# code
        static void Main(string[] args)        {            XmlDocument doc = new XmlDocument();            doc.Load("E:\\test.xml");            foreach (XmlNode node in doc.GetElementsByTagName("packet"))                GetNodes(node);        }        static void GetNodes(XmlNode node)        {            XmlAttribute showname = node.Attributes["showname"];            XmlAttribute show = node.Attributes["show"];            XmlAttribute value = node.Attributes["value"];            if (showname != null || show != null || value != null)            {                Console.Write("tagname:{0} ", node.Name);                if (showname != null)                    Console.Write("showname:{0} ", showname.Value);                if (show != null)                    Console.Write("show:{0} ", show.Value);                if (value != null)                    Console.Write("value:{0} ", value.Value);                Console.WriteLine();            }            foreach (XmlNode xn in node.ChildNodes)                GetNodes(xn);        }
[解决办法]
去下一个XMLHelp
修改一下就可以了！我这里有改好了的如果你要，给我邮箱！