怎么排除上次已查询过的值

SQL code

select  top  16  * from tbl_picinfo a  where a.[picid]>=( select max(b.[picid])  from ( select  TOP 1  [picid]  from tbl_picinfo  where 1=1    ORDER BY [picid] )b)  and a.[picid] in (select min(picid)[picid] from tbl_picinfo group by dcname,rcname)   ORDER BY a.[picid]结果:12345791013[color=#FF0000]29313235414246[/color]select  top  16  * from tbl_picinfo a  where   a.[picid]>=( select max(b.[picid])  from ( select  TOP 17  [picid]  from tbl_picinfo  where 1=1    ORDER BY [picid] )b   )  and a.[picid] in (select min(picid) [picid] from tbl_picinfo group by dcname,rcname)   ORDER BY a.[picid] [color=#FF0000]29313235414246[/color]475556626472788187

请问该怎么去掉上次已查询过的呢,我是用做分页!不能太慢,或者有什么更高效的查询,望指点!

[解决办法]
做分页？
select *
from (
select id=row_number() over (order by getdate()),* from tb ) K
where id between 1 and 10
[解决办法]
楼上的想的太多了
[解决办法]
你的是sql 2000？
那就放到一个临时表中

select id=identity(int,1,1),* into #t from tb

然后
select * from #t where id between 1 and 10