这个程序是处理四则运算的，但是出了点问题，也不是很完美，希望大家改改，谢谢
[code=C/C++][/code]
#include<stdio.h>
char put_choise();
float add_number();
float subract_number();
float multiply_number();
float divide_number();
float judge();
float judge2();
int main()
{
char getch;
while((getch=put_choise())!='q')
{
switch(getch)
{
case 'a':
printf("add_number的结果是：%.3f\n",add_number());
break;
case 's':
subract_number();
printf("sburact_number的结果是：%.3f\n",subract_number());
break;
case 'm':
multiply_number();
break;
case 'd':
divide_number();
break;
}
}
printf("Buy\n");
return 0;}
//
char put_choise()
{
printf("Enter the operation of choise:\n ");
printf("a.add\t\t\ts.subract\n");
printf("m.multiply\t\t\td.divide\nq.quit\n");
return (getchar());
}
//
float add_number()
{
float first_number,second_number;
printf("Enter first number:");
first_number=judge();
printf("Enter second number");
second_number=judge();
return (first_number+second_number);
}
//
float subract_number()
{
float first_number,second_number;
printf("Enter first number:");
first_number=judge();
printf("Enter second number");
second_number=judge();
return (first_number-second_number);
}
//
float multiply_number()
{
float first_number,second_number;
printf("Enter first number:");
first_number=judge();
printf("Enter second number");
second_number=judge();
return (first_number*second_number);
}
//
float divide_number()
{
float first_number,second_number;
printf("Enter first number:");
first_number=judge();
printf("Enter second number");
second_number=judge();
return (first_number/second_number);
}
//
float judge()
{
float first_num;
char ch;
while(scanf("%f",&first_num)==0)
{
while((ch=getchar())!='\n')
putchar(ch);
printf("Please Enter a number ,such as 2.5,-1.78E8,or3:");
}
return first_num;
}
//
float judge2()
{
float second_num;
char ch;
while(scanf("%f",&second_num)!=1)
{
while((ch=getchar())!='\n')
putchar(ch);
printf("Please Enter a number ,such as 2.5,-1.78E8,or3:");
}
return second_num;
}
[解决办法]
楼主，你judge函数是干嘛的？
- C/C++ code
#include<stdio.h>char put_choise();float add_number();float subract_number();float multiply_number();float divide_number();float judge();float judge2();int main(){ char getch; while((getch=put_choise())!='q') { switch(getch) { case 'a': printf("add_number的结果是：%.3f\n",add_number()); break; case 's': printf("sburact_number的结果是：%.3f\n",subract_number()); break; case 'm': multiply_number(); break; case 'd': divide_number(); break; } } printf("Buy\n"); return 0;}//char put_choise(){ printf("Enter the operation of choise:\n"); printf("a.add\t\t\ts.subract\n"); printf("m.multiply\t\td.divide\nq.quit\n"); fflush(stdin); return (getchar()); }//float add_number(){ float first_number,second_number; printf("Enter first number:"); first_number=judge(); printf("Enter second number:"); second_number=judge(); return (first_number+second_number);}//float subract_number(){ float first_number,second_number; printf("Enter first number:"); first_number=judge(); printf("Enter second number"); second_number=judge(); return (first_number-second_number);}//float multiply_number(){ float first_number,second_number; printf("Enter first number:"); first_number=judge(); printf("Enter second number:"); second_number=judge(); return (first_number*second_number);}//float divide_number(){ float first_number,second_number; printf("Enter first number:"); first_number=judge(); printf("Enter second number:"); second_number=judge(); return (first_number/second_number);}//float judge(){ float first_num; char ch; scanf("%f",&first_num); /* while(scanf("%f",&first_num)==0) { while((ch=getchar())!='\n') putchar(ch); printf("Please Enter a number ,such as 2.5,-1.78E8,or3:"); } */ return first_num; }//float judge2(){ float second_num; char ch; scanf("%f",&second_num);/* while(scanf("%f",&second_num)!=1) { while((ch=getchar())!='\n') putchar(ch); printf("Please Enter a number ,such as 2.5,-1.78E8,or3:"); } */ return second_num; }
[解决办法]
- C/C++ code
/*---------------------------------------函数型计算器(VC++6.0,Win32 Console)程序由 yu_hua 于2007-07-27设计完成功能：目前提供了10多个常用数学函数: ⑴正弦sin ⑵余弦cos ⑶正切tan ⑷开平方sqrt ⑸反正弦arcsin ⑹反余弦arccos ⑺反正切arctan ⑻常用对数lg ⑼自然对数ln ⑽ｅ指数exp ⑾乘幂函数∧用法：如果要求2的32次幂，可以打入2^32<回车>如果要求30度角的正切可键入tan(Pi/6)<回车>注意不能打入：tan(30)<Enter>如果要求1.23弧度的正弦，有几种方法都有效：sin(1.23)<Enter>sin 1.23 <Enter>sin1.23 <Enter>如果验证正余弦的平方和公式,可打入sin(1.23)^2+cos(1.23)^2 <Enter>或sin1.23^2+cos1.23^2 <Enter>此外两函数表达式连在一起,自动理解为相乘如：sin1.23cos0.77+cos1.23sin0.77就等价于sin(1.23)*cos(0.77)+cos(1.23)*sin(0.77)当然你还可以依据三角变换，再用sin(1.23+0.77)也即sin2验证一下。本计算器充分考虑了运算符的优先级因此诸如：2+3*4^2 实际上相当于：2+(3*(4*4))另外函数名前面如果是数字,那么自动认为二者相乘.同理，如果某数的右侧是左括号，则自动认为该数与括弧项之间隐含一乘号。如：3sin1.2^2+5cos2.1^2 相当于3*sin2(1.2)+5*cos2(2.1)又如：4(3-2(sqrt5-1)+ln2)+lg5 相当于4*(3-2*(√5 -1)+loge(2))+log10(5)此外，本计算器提供了圆周率 Pi键入字母时不区分大小写,以方便使用。----------------------------------------*/#include <iostream>#include <iomanip>#include <cstdlib>#include <cstring>#include <cctype>#include <cmath>#include <stdio.h>#include <string.h>#include <windows.h>using namespace std;const char Tab=0x9;const int DIGIT=1;const int MAXLEN=16384;char s[MAXLEN],*endss;int pcs=15;double fun(double x,char op[],int *iop) { while (op[*iop-1]<32) //本行使得函数嵌套调用时不必加括号,如 arc sin(sin(1.234)) 只需键入arc sin sin 1.234<Enter> switch (op[*iop-1]) { case 7: x=sin(x); (*iop)--;break; case 8: x=cos(x); (*iop)--;break; case 9: x=tan(x); (*iop)--;break; case 10: x=sqrt(x); (*iop)--;break; case 11: x=asin(x); (*iop)--;break; case 12: x=acos(x); (*iop)--;break; case 13: x=atan(x); (*iop)--;break; case 14: x=log10(x);(*iop)--;break; case 15: x=log(x); (*iop)--;break; case 16: x=exp(x); (*iop)--;break; } return x;}double calc(char *expr,char **addr) { static deep; //递归深度 static char *fname[]={ "sin","cos","tan","sqrt","arcsin","arccos","arctan","lg","ln","exp",NULL}; double ST[10]={0.0}; //数字栈 char op[10]={'+'}; //运算符栈 char c,*rexp,*pp,*pf; int ist=1,iop=1,last; if (!deep) { pp=pf=expr; do { c = *pp++; if (c!=' '&& c!=Tab) *pf++ = c; } while (c!='\0'); } pp=expr; if ((c=*pp)=='-'||c=='+') { op[0] = c; pp++; } last = !DIGIT; while ((c=*pp)!='\0') { if (c=='(') {//左圆括弧 deep++; ST[ist++]=calc(++pp,addr); deep--; ST[ist-1]=fun(ST[ist-1],op,&iop); pp = *addr; last = DIGIT; if (*pp == '('||isalpha(*pp) && strnicmp(pp,"Pi",2)) {//目的是：当右圆括弧的右恻为左圆括弧或函数名字时，默认其为乘法 op[iop++]='*'; last = !DIGIT; c = op[--iop]; goto operate ; } } else if (c==')') {//右圆括弧 pp++; break; } else if (isalpha(c)) { if (!strnicmp(pp,"Pi",2)) { if (last==DIGIT) { cout<< "π左侧遇）" <<endl;exit(1); } ST[ist++]=3.14159265358979323846264338328; ST[ist-1]=fun(ST[ist-1],op,&iop); pp += 2; last = DIGIT; if (!strnicmp(pp,"Pi",2)) { cout<< "两个π相连" <<endl;exit(2); } if (*pp=='(') { cout<< "π右侧遇（" <<endl;exit(3); } } else { for(int i=0; (pf=fname[i])!=NULL; i++) if (!strnicmp(pp,pf,strlen(pf)))break; if (pf!=NULL) { op[iop++] = 07+i; pp += strlen(pf); } else { cout<< "陌生函数名" <<endl;exit(4); } } } else if (c=='+'||c=='-'||c=='*'||c=='/'||c=='^') { char cc; if (last != DIGIT) { cout<< "运算符粘连" <<endl;exit(5); } pp++; if (c=='+'||c=='-') { do { cc = op[--iop]; --ist; switch (cc) { case '+': ST[ist-1] += ST[ist];break; case '-': ST[ist-1] -= ST[ist];break; case '*': ST[ist-1] *= ST[ist];break; case '/': ST[ist-1] /= ST[ist];break; case '^': ST[ist-1] = pow(ST[ist-1],ST[ist]);break; } } while (iop); op[iop++] = c; } else if (c=='*'||c=='/') {operate: cc = op[iop-1]; if (cc=='+'||cc=='-') { op[iop++] = c; } else { --ist; op[iop-1] = c; switch (cc) { case '*': ST[ist-1] *= ST[ist];break; case '/': ST[ist-1] /= ST[ist];break; case '^': ST[ist-1] = pow(ST[ist-1],ST[ist]);break; } } } else { cc = op[iop-1]; if (cc=='^') { cout<< "乘幂符连用" <<endl;exit(6); } op[iop++] = c; } last = !DIGIT; } else { if (last == DIGIT) { cout<< "两数字粘连" <<endl;exit(7); } ST[ist++]=strtod(pp,&rexp); ST[ist-1]=fun(ST[ist-1],op,&iop); if (pp == rexp) { cout<< "非法字符" <<endl;exit(8); } pp = rexp; last = DIGIT; if (*pp == '('||isalpha(*pp)) { op[iop++]='*'; last = !DIGIT; c = op[--iop]; goto operate ; } } } *addr=pp; if (iop>=ist) { cout<< "表达式有误" <<endl;exit(9); } while (iop) { --ist; switch (op[--iop]) { case '+': ST[ist-1] += ST[ist];break; case '-': ST[ist-1] -= ST[ist];break; case '*': ST[ist-1] *= ST[ist];break; case '/': ST[ist-1] /= ST[ist];break; case '^': ST[ist-1] = pow(ST[ist-1],ST[ist]);break; } } return ST[0];}int main(int argc,char **argv) { if (argc<=1) { if (GetConsoleOutputCP()!=936) system("chcp 936>NUL");//中文代码页 cout << "计算函数表达式的值。"<<endl<<"支持(),+,-,*,/,^,Pi,sin,cos,tan,sqrt,arcsin,arccos,arctan,lg,ln,exp"<<endl; while (1) { cout << "请输入表达式："; gets(s); if (s[0]==0) break;// cout << s <<"="; cout << setprecision(15) << calc(s,&endss) << endl; } } else { strncpy(s,argv[1],MAXLEN-1);s[MAXLEN-1]=0; if (argc>=3) { pcs=atoi(argv[2]); if (pcs<0||15<pcs) pcs=15; printf("%.*lf\n",pcs,calc(s,&endss)); } else { printf("%.15lg\n",calc(s,&endss)); } } return 0;}
[解决办法]
[Quote=引用:]
[code=C/C++][/code]
#include<stdio.h>
char put_choise();
float add_number();
float subract_number();
float multiply_number();
float divide_number();
float judge();
float judge2();
int main(……
[/Quote]
乘法和除法你都没有printf输出，看不到结果，减法的时候你连续调两次减法运算而减法运算中也没有输出，所以减法的时候你要连续输入两次值才能看到结果，其它的运算上没看到问题啊
[解决办法]
楼主，我那程序是改过的，你看看。
回车没吸收，导致的。
[解决办法]
用栈+后缀表达式