怎么将16进制文本转化成2进制数字？
若我读到的内容是16进制：605914F05A5B267308CA0FF01D0DF120C321F588CA0274F1B2B31EB508CA004C8C，
怎么转化成2进制数字？


[解决办法]

C/C++ code

#include<stdio.h>const char *HEX[16]= {"0000","0001","0010","0011",                      "0100","0101","0110","0111",                      "1000","1001","1010","0011",                      "0100","1101","1110","1111",                     };int main(){    const char *str="605914F05A5B267308CA0FF01D0DF120C321F588CA0274F1B2B31EB508CA004C8C";    int n=0;    const char *p=str;    while(*p)    {        sscanf(p,"%1X",&n);        puts(HEX[n]);        p++;    }    return 0;}
[解决办法]
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引用:

C/C++ code

#include<stdio.h>
const char *HEX[16]= {"0000","0001","0010","0011",
"0100","0101","0110","0111",
"1000","1001","1010","0011",
……
可是怎样将转化的值赋给一个量呢？如，data=0110000001011……

[解决办法]
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
string transferData(const string& data);
int main()
{
   string filename;
   cin >> filename; //输入问价路径
   ifstream in(filename.c_str());

   while(!in.eof(), in >> filename)
   {

       string data = filename;
       string getdata = data.substr(4, 100);
       string dddd = transferData(getdata);
       cout << dddd;
   }
   return 0;
}

string transferData(const string& data)
{
   string returndta = "";
   for(int i = 0; i < data.length(); i++)
   {
       switch(data[i])
       {
           case '0':
               returndta += "0000";
               break;
           case '1':
               returndta += "0001";
               break;
           case '2':
               returndta += "0010";
               break;
           case '3':
               returndta += "0011";
               break;
           case '4':
               returndta += "0100";
               break;
           case '5':
               returndta += "0101";
               break;
           case '6':
               returndta += "0110";
               break;
           case '7':
               returndta += "0111";
               break;
           case '8':
               returndta += "1000";
               break;
           case '9':
               returndta += "1001";
               break;
           case 'A':
               returndta += "1010";
               break;
           case 'B':
               returndta += "1011";
               break;
           case 'C':
               returndta += "1100";
               break;
           case 'D':
               returndta += "1101";
               break;
           case 'E':
               returndta += "1110";
               break;
           case 'F':
               returndta += "1111";
               break;
       }
   }
   return returndta;
}