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sql 语句乱码有关问题

发布时间: 2012-04-26 14:01:31 作者: rapoo

sql 语句乱码问题
<%@ page language="java" contentType="text/html; charset=utf-8"
pageEncoding="utf-8" import="java.sql.*" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Insert title here</title>
</head>
<body>
<form action="index2.jsp" method="post">
<select name="keyname">
<option value="city">城市</option>
<option value="">/option>
<option value=""></option>
</select>
<input type="text" name="keyvalue" value="">
<input name="submit" type="submit" value="确定"/>


</form>
<%
try{

Class.forName("com.mysql.jdbc.Driver").newInstance();
Connection connOrac = DriverManager.getConnection("jdbc:mysql://localhost/ip?user=root&password=1314521&useUnicode=true&characterEncoding=gbk");
Statement st=connOrac.createStatement();
System.out.println("ok1");

String kn = "",kv="",type="all";
String swhere = "";
request.setCharacterEncoding("utf-8");




kn =request.getParameter("keyname");

System.out.println(kn);
kv = request.getParameter("keyvalue");
System.out.println(kv);

if (kn == null){

kn = "";
}
if (kv==null){
kv = "";
}
if(!kn.equals("")&&!kv.equals("")){

swhere = "where" + kn + "like '" + kv +"%'";

}else{
swhere="";
}

System.out.println(swhere);



String sql = "select ip3 from bbsgood_ip" + swhere;

ResultSet rs = st.executeQuery(sql);

System.out.println(sql);
if(rs !=null){

while(rs.next()){
System.out.println(rs.getString("ip3"));


}

rs.close();
}
}

catch(Exception e){

System.out.print(e.getMessage());

}
%>






</body>
</html>

[解决办法]

Java code
Connection connOrac = DriverManager.getConnection("jdbc:mysql://localhost/ip?user=root&password=1314521&useUnicode=true&characterEncoding=utf8"); 

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