怎样将string转化为2进制数呢?
怎样将得到的string（如：1011001110001010110010101111100000之类）转化为2进制数呢?而不是用atoi把它转化。因为1010转化为2进制数是10，而用atoi转化则为一千零十。

[解决办法]

C/C++ code

    std::string strData = "1010";    std::bitset<32> bitData(strData);    unsigned long lData = bitData.to_ulong();
[解决办法]
from msdn:
C/C++ code
// bitset_to_ulong.cpp// compile with: /EHsc#include <bitset>#include <iostream>int main( ){   using namespace std;   bitset<5> b1 ( 7 );   cout << "The ordered set of bits in the bitset<5> b1( 7 )"        << "\n that was generated by the number 7 is: ( "        << b1 << " )" << endl;   unsigned long int i;   i = b1.to_ulong( );   cout << "The integer returned from the bitset b1,"        << "\n by the member function to_long( ), that"        << "\n generated the bits as a base two number is: "        << i << "." << endl;}