SQL替换问题
select * from user_message where address like '%2幢1单元101%' 我现在想把101变成201，原来的201变301，原来的301变401，原来的401变501，前面的幢数是1-15幢，高手给个思路，或者代码，谢谢啊

[解决办法]

SQL code

select * from user_message where address like '%2幢1单元'+cast(a + 100 as vachar(20))+'%'
[解决办法]
Delphi(Pascal) code
把%%内容用变量a代替 a:='%2幢1单元101%';{条件改变,直接改这里} sql:='select * from user_message where address like '+Quotedstr(a);