两个ArrayList 怎么进行循环比较，在线等。。。。

HTML code

有ArrayList A 跟 BAid   name1     甲1     乙1     丙2     丁2     戊3     哥Bid   name1     A1     B2     C2     D3     E3     F怎样形成一个新的ArrayList   cCAname    Bname甲        A乙        B丙        NULL丁        C戊        D哥        ENULL      F就是list A 与 list B id相等的拼起来，如果不相等，用Null代替，在线等。。。谢谢 大虾

Java code

import java.util.ArrayList;import java.util.List;class Node{    private int id ;    private String name ;        public Node(){    }    public Node(int id, String name){        this.id = id ;        this.name = name ;            }        public int getId(){        return this.id ;    }    public void setId(int id){        this.id = id ;    }            public String getName(){        return this.name ;    }    public void setName(String name){        this.name = name ;    }}class Node1{    private String name1 ;    private String name2 ;        public Node1(){    }        public Node1(String name1, String name2){        this.name1 = name1 ;        this.name2 = name2 ;    }        public String getName1(){        return this.name1 ;    }    public void setName1(String name1){        this.name1 = name1 ;    }        public String getName2(){        return this.name2 ;    }    public void setName2(String name2){        this.name2 = name2 ;    }    @Override    public String toString() {        return "Node1 [name1=" + name1 + ", name2=" + name2 + "]";    }        }public class Test3{   public static void main(String [] args){        List<Node> listA = new ArrayList<Node>() ;          listA.add(new Node(1, "甲")) ;     listA.add(new Node(1, "乙")) ;     listA.add(new Node(1, "丙")) ;     listA.add(new Node(2, "丁")) ;     listA.add(new Node(2, "戊")) ;     listA.add(new Node(3, "哥")) ;          List<Node> listB = new ArrayList<Node>() ;          listB.add(new Node(1, "A")) ;     listB.add(new Node(1, "B")) ;     listB.add(new Node(2, "C")) ;     listB.add(new Node(2, "D")) ;     listB.add(new Node(3, "E")) ;     listB.add(new Node(3, "F")) ;          int idxA = 0 , idxB = 0 ;     int oldId = -1 ;     int aId = 0, bId = 0;           Node nA = null ,nB = null ;     List<Node1> listC = new ArrayList<Node1> () ;               while(idxA < listA.size() && idxB < listB.size()){                  nA = (Node)listA.get(idxA) ;         aId = nA.getId() ;         nB = (Node)listB.get(idxB) ;         bId = nB.getId() ;                  if (oldId == -1){              oldId = nA.getId() ;         }//         System.out.println(" idxA: "+ idxA + " -- "+ aId + " -- " + oldId + " --- " + bId //                 +" -- "+ " idxB: "+  idxB);         if (aId == oldId){             if (bId == oldId){                 listC.add(new Node1(nA.getName(), nB.getName()) ) ;                  idxA++ ;                 idxB++ ;             }else{                 listC.add(new Node1(nA.getName(), null) ) ;                 idxA++ ;                              }         }else if (bId == oldId){             listC.add(new Node1(null, nB.getName()) ) ;             idxB++ ;         }else{             oldId = aId ;             if (bId == oldId){                 listC.add(new Node1(nA.getName(), nB.getName()) ) ;                  idxA++ ;                 idxB++ ;             }else{                 listC.add(new Node1(nA.getName(), null) ) ;                 idxA++ ;                              }                      }     }     while(idxA < listA.size()){         nA = listA.get(idxA) ;         idxA++ ;         listC.add(new Node1(nA.getName(), null) ) ;      }          while(idxB < listB.size()){         nB = listB.get(idxB) ;         idxB++ ;         listC.add(new Node1(null, nB.getName()) ) ;      }          for (int i =0 ; i < listC.size(); i++){         System.out.println(listC.get(i).toString()) ;              }        }} 
 
[解决办法]
Java code
public class ArrayTest {    public static void main(String args[]) {        List<String[]> a = new ArrayList<String[]>();        List<String[]> b = new ArrayList<String[]>();        String[] a1 = { "1", "一" };        String[] a2 = { "1", "二" };        String[] a3 = { "1", "三" };        String[] a4 = { "2", "四" };        String[] a5 = { "2", "五" };        String[] a6 = { "3", "六" };        a.add(a1);a.add(a2);a.add(a3);a.add(a4);a.add(a5);a.add(a6);        String[] b1 = { "1", "A" };        String[] b2 = { "1", "B" };        String[] b3 = { "2", "C" };        String[] b4 = { "2", "D" };        String[] b5 = { "3", "E" };        String[] b6 = { "3", "F" };        String[] b7 = { "4", "G" };        b.add(b1);b.add(b2);b.add(b3);b.add(b4);b.add(b5);b.add(b6);b.add(b7);        List<String[]> result = new ArrayList<String[]>();        int indexA = 0;        int indexB = 0;                for (int i = 0; i < Math.max(a.size(),b.size()); i++) {            String[] temp1 = new String[2];            String[] temp2 = new String[2];            if(indexA < a.size()){                temp1 = a.get(indexA);            }            else{                temp1[0] = ""+Integer.MAX_VALUE;                temp1[1] = null;            }            if(indexB < b.size()){                temp2 = b.get(indexB);            }            else{                temp2[0] =""+Integer.MAX_VALUE;                temp2[1] = "null";            }            String[] tempResult = new String[2];            if (temp1[0].equals(temp2[0])){                tempResult[0] = temp1[1];                tempResult[1] = temp2[1];                result.add(tempResult);                indexA++;                indexB++;            } else if (Integer.parseInt(temp1[0]) > Integer.parseInt(temp2[0])) {                tempResult[0] = "null";                tempResult[1] = temp2[1];                result.add(tempResult);                indexB++;            } else if (Integer.parseInt(temp1[0]) < Integer.parseInt(temp2[0])) {                tempResult[0] = temp1[1];                tempResult[1] = "null";                result.add(tempResult);                indexA++;            }        }        for(String[] ss:result){            System.out.println(ss[0]+","+ss[1]);        }    }}