求一个正则表达式。另外求正则表达式学习资料

Java code

      public static final int openedHandle=0x7f010007;        /**  Defines panel position on the screen.          <p>Must be one of the following constant values.</p><table><colgroup align="left" /><colgroup align="left" /><colgroup align="left" /><tr><th>Constant</th><th>Value</th><th>Description</th></tr><tr><td><code>top</code></td><td>0</td><td> Panel placed at top of the screen. </td></tr><tr><td><code>bottom</code></td><td>1</td><td> Panel placed at bottom of the screen. </td></tr><tr><td><code>left</code></td><td>2</td><td> Panel placed at left of the screen. </td></tr><tr><td><code>right</code></td><td>3</td><td> Panel placed at right of the screen. </td></tr></table>         */        public static final int position=0x7f010001;

大概是上面这样子，我需要匹配出 openedHandle出来即可。

当然实际上我可以先判断每行有没有public static final int这个字符串，有的话就trim一下，在把=号以及后面的去掉，之后再截一下字符串就可以了。但太复杂了。。。有需求才有进步，借此想认真的学一下正则表达式，之前自己学的那些只能匹配简单的。一复杂就不行了

[解决办法]
你这个问题太简单，自己去花30分钟看看，30分钟快速入门到精通正则：
http://www.cnblogs.com/deerchao/archive/2006/08/24/zhengzhe30fengzhongjiaocheng.html
[解决办法]
for example

Java code

Scanner sc = new Scanner(new FileInputStream("your_file"));String regex = "(?i).*?public static final int (.*?)\\s*=.*";Pattern p = Pattern.compile(regex);while (sc.hasNext()) {    String buf = sc.nextLine();    if (! buf.matches(regex)) continue;    Matcher m = p.matcher(buf);    while (m.find()) System.out.println(m.group(1));}