js输出的html代码在谷歌游览器的显示问题
- JScript code
if(document.getElementById("showworkplanreminddiv")) { var str=""; str+="<div width='30%' height='10%'>"; str+="<table width='100%' height='100%' border='0'>"; str+="<tr>"; str+="<td colspan='6' style='background-image:url(publicimages/lcy_messageblue.png);'> </td>"; str+="</tr>"; str+="<tr>"; str+="<td width='87'> </td>"; str+="<td colspan='2' rowspan='4' align='left'><img src='publicimages/lcy_message.jpg'/></td>"; str+="<td width='72'> </td>"; str+="<td width='87'> </td>"; str+="<td width='92'> </td>"; str+="</tr>"; str+="<tr>"; str+="<td> </td>"; str+="<td colspan='3' rowspan='2' align='center' ><strong>日程提醒!</strong></td>"; str+="</tr>"; str+="<tr>"; str+="<td> </td>"; str+="</tr>"; str+="<tr>"; str+="<td> </td>"; str+="<td> </td>"; str+="<td> </td>"; str+="<td> </td>"; str+="</tr>"; str+="<tr>"; str+="<td colspan='3' align='right' width='50%' height='10%' valign='middle'><a href='#' onclick='lcy_remindtiaozhuan(\""+workplanid+"\")' title='打开'><img src='publicimages/lcy_open.jpg' border='0'/></a> </td>"; str+="<td colspan='3' align='left' width='50%' height='10%' valign='middle'> <a href='#' title='关闭' onclick='closeremind()'><img src='publicimages/lcy_close.jpg' border='0'/></a></td>"; str+="</tr>"; str+="</table>"; str+="</div>";//11:42 $("#showworkplanreminddiv").css("display",""); $("#showtoumingdiv").css("display",""); document.getElementById("showworkplanreminddiv").innerHTML=str; }//if end- HTML code
<div id=\"showworkplanreminddiv\" name=\"showworkplanreminddiv\" style=\"display:none\"></div>
js输出的html代码在ie6和ie8上都好用，在谷歌游览器上却显示不出来，这是什么原因啊？请各位前辈们给看看
[解决办法]
<div id=\"showworkplanreminddiv\" name=\"showworkplanreminddiv\" style=\"display:none\"></div>
你这个html又不是字符串，干嘛要转义 双引号