数组求和用指针表示。。。。
下面这段代码，是一个例子。2维数组的。要求不使用数组下标，而是使用指针进行计算。
我思考去思考来，必须得用下标呀；指针咋样不用for循环，直接计算呢》？

C/C++ code

#include<stdio.h>#define MONTHS 12#define YEARS 5int main(void){    const float rain[YEARS][MONTHS]={        {4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6},        {8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3},        {9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4},        {7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2},        {7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2}    };    int year,month;    float subtot,total;    printf("  YEAR   RAINFALL  (inches)\n");    for(year=0,total=0;year<YEARS;year++)    {        for(month=0,subtot=0;month<MONTHS;month++)            subtot+=rain[year][month];        printf("%5d %15.1f\n",2000+year,subtot);        total+=subtot;    }    printf("\nThe yearly average is %.1f inches.\n\n",total/YEARS);    printf("MONTHLY AVERAGE;\n\n");    printf("  Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec\n");    for(month=0;month<MONTHS;month++)    {        for(year=0,subtot=0;year<YEARS;year++)            subtot+=rain[year][month];        printf("%4.1f",subtot/YEARS);    }    printf("\n");    return 0;}

[解决办法]
不用下标只是说不用rand[i][j]的方式，你换成二维指针就行了 *(*(rand+i)+j) 其他的循环方式都一样