存到文件中的数字以10个一行显示。
#include <stdio.h>
#include <stdlib.h>
main()
{
FILE *fp;
char ch;
int count;
if((fp=fopen("d:\\111\\222\\num.txt","wt+"))==NULL)
{
printf("不能找到文件!");
getchar();
exit(1);
}
printf("输入数字:\n");
ch=getchar();
while (ch!='\n')
{
fputc(ch,fp);
ch=getchar();
count++;
}
rewind(fp);
ch=fgetc(fp);
while(ch!=EOF)
{
if (count % 10 == 0) { //十个换行输出
putchar('\n');
} else {
putchar(ch);
}
//putchar(ch);
ch=fgetc(fp);

}
printf("\n");
fclose(fp);
}

[解决办法]

C/C++ code

#include <stdio.h>  #include <stdlib.h>int main()  {      FILE *fp;      char ch;      int count = 0;//count要初始化    if((fp=fopen("d:\\num.txt","wt+"))==NULL)      {          printf("不能找到文件!");          getchar();          exit(1);      }      printf("输入数字:\n");      ch=getchar();      while (ch!='\n')      {          fputc(ch,fp);        ch=getchar();          count++;    }      rewind(fp);      ch=fgetc(fp);      while(ch!=EOF)      {          if (count % 10 == 0)         { //十个换行输出        putchar('\n');        }         else         {            putchar(ch);        }        ch=fgetc(fp);    }      printf("\n");      fclose(fp);  }