求一正则 提取字符串
字符串：

C# code

[[-1,"bjs","北京",123432,"AAEE66",[[11561,"bj","aacc55","bjs","tt"],[11561,"Q","aacc55","bjs","QUINELLA"]],"中国"],[-1,"AG","梅特兰s",123436,"FF88CC",[[11464,"AU","dd88cc","AUs","dd"]],"澳洲"]]

提取出：
北京 11561 bj 中国
北京 11561 Q 中国
梅特兰s 11464 AU 澳洲

[解决办法]
只有一个 "中国" ，怎么会提取出两个出来...
[解决办法]
解析JSON会比较容易
[解决办法]
数据样本较少，不一定符合所有情况

C# code

string test = @"[[-1,""bjs"",""北京"",123432,""AAEE66"",[[11561,""bj"",""aacc55"",""bjs"",""tt""],[11561,""Q"",""aacc55"",""bjs"",""QUINELLA""]],""中国""],[-1,""AG"",""梅特兰s"",123436,""FF88CC"",[[11464,""AU"",""dd88cc"",""AUs"",""dd""]],""澳洲""]]";Regex reg = new Regex(@"\[-1,[^,]+,""([^""]*)"",[^\[]+\[(?:\[(\d+),""([^""]*)""[^\]]*\],?\s*)*\],""([^""]*)""\]");MatchCollection mc = reg.Matches(test);foreach (Match m in mc){    foreach (Capture c in m.Groups[3].Captures)    {        richTextBox2.Text += m.Groups[1].Value + " " + m.Groups[2].Value + " " + c + " " + m.Groups[4].Value + "\n";    }}/*-----输出-----北京 11561 bj 中国北京 11561 Q 中国梅特兰s 11464 AU 澳洲*/