java给定前后字符串如何获取中间字符串

如题

[解决办法]

Java code

   String str="aaaaxxxxxxxxbbbb";        String begin="aaaa";        String end="bbbb";        Matcher m=Pattern.compile("^"+begin+"(.*)"+end+"$").matcher(str);        if(m.find())            System.out.println(m.group(1));
[解决办法]
Java code
public class Test {    /**     * @param args     */    public static void main(String[] args) {        // TODO Auto-generated method stub        String s="nimabi";        String pre="ni";        String suf="bi";        System.out.println(s.substring((s.indexOf(pre)+pre.length()), s.indexOf(suf)));    }}
[解决办法]
Java code
    static String getStr(String src,String beg,String end){        String regex = beg+"(.*)"+end;        System.out.println(regex);        Pattern p = Pattern.compile(regex);        Matcher m = p.matcher(src);        if(m.find()){            return m.group(1);        }                return null;    }    public static void main(String[] args)    {        System.out.println(getStr("aaa12121212dde", "aaa", "dde"));    }
[解决办法]
Java code
    public static void main(String[] args) {        String s = "楼主你给我100分!";        String mid = s.replaceAll(".*你(.*)!.*", "$1");        System.out.println(mid);    }
[解决办法]
package com.xuyisen.socket.socket;

public class Test {

/**
 * 截取字符串source中begin到end之间的字符串
 * @param source 源字符串
 * @param begin 开始
 * @param end 结束
 * @return
 */
public String subString(String source,String begin, String end){
String result = "";
if(!source.contains(begin)){
result = "源字符串中没有字符串: " + begin;
return result;
}else if(!source.contains(end)){
result = "源字符串中没有字符串: " + end;
return result;
}
int beginIndex = source.indexOf(begin);
int endIndex = source.indexOf(end);
result = source.substring(beginIndex+begin.length(), endIndex);
return result;
}

public static void main(String[] args) {
Test t = new Test();

String str = "louzhugeiwojiafen,ok";
String begin = "louzhu";
String end = ",ok";

String s = t.subString(str, begin, end);
System.out.println(s);
}
}