md5解密问题
请问这个怎么解密啊
592a0897d669ad6c

用的这个文件md5.asp代码如下（分两次发 贴在太长发不了）

<%
Private Const BITS_TO_A_BYTE = 8
Private Const BYTES_TO_A_WORD = 4
Private Const BITS_TO_A_WORD = 32

Private m_lOnBits(30)
Private m_l2Power(30)
Dim Md5OLD
Private Function LShift(lValue, iShiftBits)
If iShiftBits = 0 Then
LShift = lValue
Exit Function
ElseIf iShiftBits = 31 Then
If lValue And 1 Then
LShift = &H80000000
Else
LShift = 0
End If
Exit Function
ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
Err.Raise 6
End If

If (lValue And m_l2Power(31 - iShiftBits)) Then
LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * m_l2Power(iShiftBits)) Or &H80000000
Else
LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * m_l2Power(iShiftBits))
End If
End Function

Private Function str2bin(varstr)
Dim varasc
Dim i
Dim varchar
Dim varlow
Dim varhigh

str2bin=""
For i=1 To Len(varstr)
varchar=mid(varstr,i,1)
varasc = Asc(varchar)

If varasc<0 Then
varasc = varasc + 65535
End If

If varasc>255 Then
varlow = Left(Hex(Asc(varchar)),2)
varhigh = right(Hex(Asc(varchar)),2)
str2bin = str2bin & chrB("&H" & varlow) & chrB("&H" & varhigh)
Else
str2bin = str2bin & chrB(AscB(varchar))
End If
Next
End Function

Private Function RShift(lValue, iShiftBits)
If iShiftBits = 0 Then
RShift = lValue
Exit Function
ElseIf iShiftBits = 31 Then
If lValue And &H80000000 Then
RShift = 1
Else
RShift = 0
End If
Exit Function
ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
Err.Raise 6
End If

RShift = (lValue And &H7FFFFFFE) \ m_l2Power(iShiftBits)

If (lValue And &H80000000) Then
RShift = (RShift Or (&H40000000 \ m_l2Power(iShiftBits - 1)))
End If
End Function

Private Function RotateLeft(lValue, iShiftBits)
RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End Function

Private Function AddUnsigned(lX, lY)
Dim lX4
Dim lY4
Dim lX8
Dim lY8
Dim lResult

lX8 = lX And &H80000000
lY8 = lY And &H80000000
lX4 = lX And &H40000000
lY4 = lY And &H40000000

lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)

If lX4 And lY4 Then
lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
ElseIf lX4 Or lY4 Then
If lResult And &H40000000 Then
lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
Else
lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
End If
Else
lResult = lResult Xor lX8 Xor lY8
End If

AddUnsigned = lResult
End Function

Private Function md5_F(x, y, z)
md5_F = (x And y) Or ((Not x) And z)
End Function

Private Function md5_G(x, y, z)
md5_G = (x And z) Or (y And (Not z))
End Function

Private Function md5_H(x, y, z)
md5_H = (x Xor y Xor z)
End Function

Private Function md5_I(x, y, z)
md5_I = (y Xor (x Or (Not z)))
End Function

Private Sub md5_FF(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_F(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)

End Sub

Private Sub md5_GG(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_G(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub

Private Sub md5_HH(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_H(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub

Private Sub md5_II(a, b, c, d, x, s, ac)
a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_I(b, c, d), x), ac))
a = RotateLeft(a, s)
a = AddUnsigned(a, b)
End Sub

Private Function ConvertToWordArray(sMessage)
Dim lMessageLength
Dim lNumberOfWords
Dim lWordArray()
Dim lBytePosition
Dim lByteCount
Dim lWordCount
Const MODULUS_BITS = 512
Const CONGRUENT_BITS = 448
If Md5OLD = 1 Then
lMessageLength = Len(sMessage)
Else
lMessageLength = LenB(sMessage)
End If

[解决办法]
不明白你为什么要解密md5，这个算法现在只能靠字典比对出来，直接解密不行。
[解决办法]
md5不可逆 ，目前还没听闻能破译的
[解决办法]
恩，没错，没法解回来，但是可以对比吧。可以比较一段密文是不是由某个明文加密的，是/不是,而已。
[解决办法]
这个破解不了吧