appfuse 2.0 框架怎么做两个不同的登陆页面
我现在用APPFUSE框架做项目，前台有一个会员登录。后台有管理员的登陆，由于appfuse用的是spring
spring-security-2.0.1 自己对于这个配置不是很懂，希望有经验的前辈指点下，谢谢
配置如下：需要更多，我可以都贴出来。急帮忙解决，谢谢！

XML code

<?xml version="1.0" encoding="UTF-8"?><beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"             xmlns:beans="http://www.springframework.org/schema/beans"             xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd              http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-2.0.1.xsd">    <http auto-config="true" lowercase-comparisons="false">        <!--intercept-url pattern="/images/*" filters="none"/>        <intercept-url pattern="/styles/*" filters="none"/>        <intercept-url pattern="/scripts/*" filters="none"/-->        <intercept-url pattern="/system.html" access="ROLE_ADMIN"/>        <intercept-url pattern="/system/*" access="ROLE_ADMIN"/>        <intercept-url pattern="/admin/*" access="ROLE_ADMIN"/>        <intercept-url pattern="/member/*" access="ROLE_ADMIN,ROLE_USER"/>        <intercept-url pattern="/passwordHint.html*" access="ROLE_ANONYMOUS,ROLE_ADMIN,ROLE_USER"/>        <intercept-url pattern="/signup.html*" access="ROLE_ANONYMOUS,ROLE_ADMIN,ROLE_USER"/>        <intercept-url pattern="/a4j.res/*.html*" access="ROLE_ANONYMOUS,ROLE_ADMIN,ROLE_USER"/>        <!-- APF-737, OK to remove line below if you're not using JSF -->        <intercept-url pattern="/**/*.html*" access="ROLE_ANONYMOUS,ROLE_ADMIN,ROLE_USER"/>                <form-login login-page="/login.jsp" authentication-failure-url="/login.jsp?error=true" login-processing-url="/j_security_check"/>        <remember-me user-service-ref="userDao" key="e37f4b31-0c45-11dd-bd0b-0800200c9a66"/>    </http>    <authentication-provider user-service-ref="userDao">        <password-encoder ref="passwordEncoder"/>    </authentication-provider>    <!-- Override the default password-encoder (SHA) by uncommenting the following and changing the class -->    <!-- <bean id="passwordEncoder" class="org.springframework.security.providers.encoding.ShaPasswordEncoder"/> -->    <global-method-security>        <protect-pointcut expression="execution(* *..service.UserManager.getUsers(..))" access="ROLE_ADMIN"/>        <protect-pointcut expression="execution(* *..service.UserManager.removeUser(..))" access="ROLE_ADMIN"/>    </global-method-security></beans:beans>

APPFUSE 2.0

[解决办法]
顶下 没学过
[解决办法]
你贴出来的是security.xml配置，这类配好了URL的pattern的访问权限，即pattern和role之间的对应关系。这里定义了3种role: ROLE_ANONYMOUS,ROLE_ADMIN,ROLE_USER。

你可以直接使用AppFuse内置的管理员账号admin用于后端，对于前端若你想自己创建一个一般用户，只要在AppFuse里，在src/test/resources/sample-data.xml中，照着里面user账号，自己写一个一般用户表记录，再配好role表的对应关系，再运行mvn clean package，让maven把你自己的账号存入数据库就好了。