看看谁能有更简单的方法，大牛们出招吧！！！！！！

今天比较闲暇，写了一个小程序，就是一个登录相关的

从键盘中输入，用main方法接收，user：abc 和password:123

当输入错误时，应该再次输入用户名和密码，知道正确为止。

以下是我的实现方式，我想看看谁有更简单的没有，欢迎指点：

LoginEntity

Java code

public class LoginEntity {    private String name;    private String password;        public LoginEntity(String name,String password){        this.name = name;        this.password = password;    }        public boolean validate(){        if(name.equals("abc")&&password.equals("123")){            return true;        }else{            return false;        }                }}

Operate

Java code

import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;public class Operate {    private String str[];        public Operate(String str[]){        this.str = str;        if(str.length!=2){            System.out.println("输入的参数不正确");            System.exit(1);            //JVM运行终止，设置一个非0的参数即可        }    }        //用户再次输入    public static void inputTest(){                        System.out.println("请再次输入用户名和密码");                                String str[] = new String[2];            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));                        for (int i = 0; i < str.length; i++) {                try {                    str[i] = br.readLine();                } catch (IOException e) {                    // TODO Auto-generated catch block                    e.printStackTrace();                }            }                                }        public boolean getInfo(){        if(new LoginEntity(this.str[0], this.str[1]).validate()){            return true;        }else{            return false;        }    }}

Login

Java code

package mystudy.j2se.DemoLogin02;import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;public class Login {    public static void main(String[] args) {                System.out.println("请输入用户名和密码");                String str[] = new String[2];        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));                for (int i = 0; i < str.length; i++) {            try {                str[i] = br.readLine();            } catch (IOException e) {                // TODO Auto-generated catch block                e.printStackTrace();            }        }                        Operate o = new Operate(str);                if(!o.getInfo()){            System.out.println("登录失败");                        o.inputTest();                    }else{            System.out.println("登陆成功");        }            }        }

谢谢大家指点， 看看有木有 更简单的

[解决办法]
public boolean validate(){
if(name.equals("abc")&&password.equals("123")){
return true;
}else{
return false;
}

}
public boolean getInfo(){
if(new LoginEntity(this.str[0], this.str[1]).validate()){
return true;
}else{
return false;
}
}
这两处的判断有点像画蛇添足。
直接return name.equals("abc")&&password.equals("123");
return new LoginEntity(this.str[0], this.str[1]).validate();
------解决方案--------------------

package study19.Account;

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class AccountDemo {

public static void main(String[] args) {
AccountManager manager = new AccountManager();
Scanner console = new Scanner(System.in);
while(true){
showMenu();
String cmd = console.nextLine().trim();
if("0".equals(cmd)){
System.out.println("下次见！");
break;
}else if("1".equals(cmd)){
System.out.println
("输入你的注册信息格式是：邮箱 密码，如：tom@gamil.com 123456");
String someuser = console.nextLine();
someuser.matches
("^\\s*\\w+(?:\\.{0,1}[\\w-]+)*@[a-zA-Z0-9]+" +
"(?:[-.][a-zA-Z0-9]+)*\\.[a-zA-Z]+\\s*$" );
String[] data = someuser.split("\\s+");
try{
User user = manager.reg(data[0], data[1]);
System.out.println("注册成功："+user);
}catch(EmailExistException e){
System.out.println(e.getMessage());
}catch(Pwd2ShortException e){
System.out.println(e.getMessage());
}catch(ArrayIndexOutOfBoundsException e){
System.out.println(e.getMessage());
}

}else if("2".equals(cmd)){
System.out.println
("输入你的登录,信息格式是：邮箱 密码，如：tom@gamil.com 123456");
String someuser = console.nextLine();
//匹配邮箱正则表达

someuser.matches
("^\\s*\\w+*@[a-zA-Z0-9]+" +
"(\\.[a-zA-Z0-9]+)*\\.[a-zA-Z]+\\s*$" );
String[] data = someuser.split("\\s+");
try{
User user = manager.login(data[0], data[1]);
System.out.println("登录成功！"+user);
}catch(EmailOrPwdException e){
System.out.println(e.getMessage());
}catch(ArrayIndexOutOfBoundsException e){
e.printStackTrace();
}

}else
System.out.println("命令错误！");

}
}
public static void showMenu(){
System.out.println("欢迎使用，请输入你的选择：");
System.out.println("***********************");
System.out.println("1:注册帐号");
System.out.println("2:登录帐号");
System.out.println("0:退出");
}

}
//帐号管理
class AccountManager{
private Map<String, User> users=
new HashMap<String, User>();
private int id = 1;
//用邮箱注册
public User reg(String email,String pwd)
throws EmailExistException,Pwd2ShortException{//异常的使用
if(pwd == null || pwd.length()<6){
throw new Pwd2ShortException("密码太短了！");
}
if(users.containsKey(email)){
throw new EmailExistException("用户已经存在！");
}
User someone = new User(id++, email, pwd);
users.put(email, someone);
return someone;

}
//登录
public User login(String email,String pwd)
throws EmailOrPwdException{
User one = users.get(email);
if(one == null)
System.out.println("查无此人！");
if(one.getPwd().equals(pwd))
return one;
throw new EmailOrPwdException("密码错误！");
}

}

class User{
private int id;
private String email;
private String pwd;
public User() {
// TODO Auto-generated constructor stub
}
public User(int id, String email, String pwd) {
super();
this.id = id;
this.email = email;
this.pwd = pwd;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPwd() {
return pwd;
}
public void setPwd(String pwd) {

this.pwd = pwd;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + id;
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
User other = (User) obj;
if (id != other.id)
return false;
return true;
}
@Override
public String toString() {
return "User [email=" + email + ", id=" + id + "]";
}


}
/**自定义异常必须继承于Exception
* 手动继承所有父类构造器
* */
class EmailExistException extends Exception{

public EmailExistException() {
super();
// TODO Auto-generated constructor stub
}

public EmailExistException(String message, Throwable cause) {
super(message, cause);
// TODO Auto-generated constructor stub
}

public EmailExistException(String message) {
super(message);
// TODO Auto-generated constructor stub
}

public EmailExistException(Throwable cause) {
super(cause);
// TODO Auto-generated constructor stub
}


}
class Pwd2ShortException extends Exception{


public Pwd2ShortException() {
super();
}


public Pwd2ShortException(String message, Throwable cause) {
super(message, cause);

}

public Pwd2ShortException(String message) {
super(message);

}


public Pwd2ShortException(Throwable cause) {
super(cause);

}

}
class EmailOrPwdException extends Exception{



public EmailOrPwdException() {
super();
// TODO Auto-generated constructor stub
}

public EmailOrPwdException(String message, Throwable cause) {
super(message, cause);
// TODO Auto-generated constructor stub
}

public EmailOrPwdException(String message) {
super(message);
// TODO Auto-generated constructor stub
}

public EmailOrPwdException(Throwable cause) {
super(cause);
// TODO Auto-generated constructor stub
}

}





[解决办法]
最简单这样：
1，验证用户名密码是否正确，如果错误，直接关闭程序，关闭前告诉他，不嫌麻烦就继续输入错误吧；
2，这样程序就很简单了，保证一次成功；

哈哈。。。。。。。。。。。。。
[解决办法]
如果你仅仅是为了求代码最简化，为啥还要搞出3个类？

Java code

    public static void main(String[] args) throws Exception {        Scanner sc = new Scanner(System.in);        while (true) {            System.out.print("UserName: ");            String name = sc.next();            System.out.print("Password: ");            String pass = sc.next();            if (name.equals("abc") && pass.equals("123"))break;            System.out.println("WRONG! Please input again.");        }        System.out.println("Welcome baby!");    }