有点难的查询，请求帮忙？《有点难的查询，请求帮忙？〉
销售表x_sale
sale_id sale_addtime sale_money
1 2012-01-01 500
2 2012-01-01 500
3 2012-01-02 300

销售退货表x_saleout
saleout_id saleout_addtime saleout_money
1 2012-01-01 100
1 2012-01-01 100
2 2012-01-03 200

如何才能得到
addtime sale_money saleout_money money
2012-01-01 1000 200 800
2012-01-02 300 0 300
2012-01-03 0 200 -200

就是同时得到两个表的数据，并且带子查询的。

[解决办法]

SQL code

--> 测试数据：[x_sale]if object_id('[x_sale]') is not null drop table [x_sale]create table [x_sale]([sale_id] int,[sale_addtime] datetime,[sale_money] int)insert [x_sale]select 1,'2012-01-01',500 union allselect 2,'2012-01-01',500 union allselect 3,'2012-01-02',300--> 测试数据：[x_saleout]if object_id('[x_saleout]') is not null drop table [x_saleout]create table [x_saleout]([saleout_id] int,[saleout_addtime] datetime,[saleout_money] int)insert [x_saleout]select 1,'2012-01-01',100 union allselect 1,'2012-01-01',100 union allselect 2,'2012-01-03',200with tas(select     [sale_addtime],    SUM([sale_money]) [sale_money]from     [x_sale]group by     [sale_addtime]),m as(select     [saleout_addtime],    SUM([saleout_money]) as [saleout_money]from     [x_saleout]group by    [saleout_addtime])select     isnull(t.sale_addtime,m.saleout_addtime) as addtime,    isnull(t.sale_money,0) as sale_money,    isnull(m.saleout_money,0) as saleout_money,    isnull(t.sale_money,0)-isnull(m.saleout_money,0) as [money]from     t full join     m on     t.sale_addtime=m.saleout_addtime/*addtime    sale_money    saleout_money    money---------------------------------------------------2012-01-01 00:00:00.000    1000    200    8002012-01-02 00:00:00.000    300    0    3002012-01-03 00:00:00.000    0    200    -200*/