list index out of range 求解
import os,re,linecache
def fun(path):
for root,dirs,files in os.walk(path):
for fn in files:
rootpath = os.path.join(root,fn)
filetype=fn.split('.')[1]
if filetype in['xml']:
print(rootpath)
new=(linecache.getline(rootpath,4)).rstrip()
print (new)
#print (type(new))
newsp=new.split('.')
#print (type(newsp))
print(newsp[1])
f= open(rootpath,'r+')
d=f.read()
open(rootpath, 'w').write(re.sub(r'a', 'b', d))
f.close()
else:
continue
fun(r'C:\wmpub')



C:\wmpub\a.xml

Traceback (most recent call last):
File "C:\Documents and Settings\Administrator\桌面\test.py", line 21, in <module>
fun(r'C:\wmpub')
File "C:\Documents and Settings\Administrator\桌面\test.py", line 14, in fun
print(newsp[1])
IndexError: list index out of range
>>>

[解决办法]
print(newsp[1])这里,newsp要么是个空list[],要么长度是1,没有[1],只有[0]
建议你print之前做个判断

if len(newsp)>1:
print(newsp[1])
else:
print(newsp)
[解决办法]
意思是你访问的东西已经超出了数组的界限
[解决办法]

Python code

#!/usr/bin/pythonimport os,re,linecachedef walkFilesInPath(path, extfilter='.xml'):    for root, dirs, files in os.walk(path):        for filename in files:            if os.path.splitext(filename)[1] == extfilter:                yield os.path.join(root, filename)def processFile(filename):    newsp = (linecache.getline(filename,4)).rstrip().split('.')    print(newsp)def fun(path):    for filename in walkFilesInPath(path, extfilter='.xml'):        processFile(filename)fun(r'C:\wmpub')