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jquery ajax 传参有关问题

发布时间: 2012-06-24 19:01:53 作者: rapoo

jquery ajax 传参问题

前段时间为了一个参数折腾一天,也不知为什么会这样,发现只要data参数里面带phone的关键字就传不过去,不知是咋回事,很是不爽,在此一提,希望有高人指点一下。

测试页:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>测试</title>
<script src="/newindex/js/jquery-1.4.4.min.js"></script>

<script type="text/javascript">
function aa(){

$.ajax({
type:"GET",
url:"Chuli.jsp",

data:"phone=15900233744&username=黑蛋&userimg=1&usersex=男&ttt="+Math.random(),
error:function(){
alert("服务器繁忙,请稍候在试!");
},
success:function(msg){
var return_info=msg.replace(/(^\s*)|(\s*$)/g, "");
if(return_info=="hel"){
alert("成功");
}
}
});

}
</script>

</head>

<body>
<input type="button" onclick="aa()" value="测试" />
</body>
</html>

Chuli.jsp页面:

<%@ page language="java" import="java.util.*,java.io.PrintWriter" pageEncoding="UTF-8"%>

<%
PrintWriter out2 = response.getWriter();

String phone = request.getParameter("phone");
String username = request.getParameter("username");
String userimg = request.getParameter("userimg");
String usersex = request.getParameter("usersex");

System.out.println("uname"+username);

String str="hel";
out2.print(str);
out2.flush();
out2.close();

%>

只要data参数里带phone就报alert("服务器繁忙,请稍候在试!");不知是怎么回事,求高人指点!!!!!!!!!

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