第一个servlet各种碰钉子，新手求指教

第一个servlet各种碰壁，新手求指教
我直接把代码贴出来吧
这个是前台网页
<body bgcolor = "cccfff">
<FORM method = "post" action = "aa">
<P>数据1<INPUT type = "text" name = "gr1"></P>
<P>数据1<INPUT type = "text" name = "gr2"></P>
<P>数据1<INPUT type = "text" name = "gr3"></P>
<P><INPUT type = "submit" value = "提交">
<INPUT type = "reset" value = "清除">
</P>
</FORM>

</body>

这个是servlet程序

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class aa extends HttpServlet {
protected void processRequest(HttpServletRequest request , HttpServletResponse response)throws ServletException , IOException{
response.setContentType("text/html ; charset = UTF-8");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head>");
out.println("<title>getParams</title>");
out.println("</head>");
out.println("<body>");
out.println(request.getParameter("gr1") + "<br>");
out.println(request.getParameter("gr2") + "<br>");
out.println(request.getParameter("gr3") + "<br>");
out.println("<html>");
out.println("<html>");
out.println("</body>");
out.println("</html>");
}

protected void doGet(HttpServletRequest request , HttpServletResponse response)throws ServletException , IOException{
processRequest(request,response);
}
protected void doPost(HttpServletRequest request , HttpServletResponse response)throws ServletException , IOException{
processRequest(request,response);
}
}

这个是web.xml的配置文件
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<servlet>

<servlet-name>aa</servlet-name>
<servlet-class>aa</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>aa</servlet-name>
<url-pattern>/aa</url-pattern>
</servlet-mapping>

</web-app>

问题是这样的我点击提交按钮理论上应该是跳到servlet显示出各个文本框的内容不过我点击提交出现的却是下载页面点击下载然后aa就被下载下来了

[解决办法]
果断换一个试试看？
[解决办法]
你这个问题我已经出现多次了。是你编码方式写错了

response.setContentType("text/html ; charset = UTF-8"); 这地方有问题、
[解决办法]
还有看你把doget、dopost里面自动生成的都给删了这样写不麻烦么、
给你个小例子看下吧

Java code

public void doGet(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        response.setContentType("text/html");        //PrintWriter out = response.getWriter();        doPost(request,response);        //out.flush();        //out.close();    }        public void doPost(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        response.setContentType("text/html;charset=GBK");        response.setCharacterEncoding("GBK");        List&lt;Profile&gt; profileList = null;        try {            profileList =profileBiz.getAll();        } catch (SQLException e) {            // TODO Auto-generated catch block            e.printStackTrace();        }        request.getSession().setAttribute("profiles", profileList);        PrintWriter out = response.getWriter();                out.flush();        out.close();    } 
 
[解决办法]
嗯，知道，你的aa继承了HttpServlet这个父类，所以&lt;servlet-class&gt;aa&lt;/servlet-class&gt;写aa的全路径啊，（把鼠标放在aa这个类上，然后摁下F2，就能看见全路径，然后复制粘贴到&lt;servlet-class&gt;aa&lt;/servlet-class&gt;这个里面）

第一个servlet各种碰钉子新手求指教

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