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Activiti工作流资源的获取跟存储实现

发布时间: 2012-07-02 17:46:22 作者: rapoo

Activiti工作流资源的获取和存储实现

???? 前两天同事问我,工作流activiti通过activiti-probe部署时候上传的工作流配置文件到存在哪里。我当时懵了,当时知道在数据库存储工作流资源文件的信息。但是不知道文件系统是否存有。于是,研究一下源代码明白,资源信息存储和获取的结构如下:

?在工作流Activiti中流程xml文件和流程图片的存储和实现:

在工作流部署的时候需要上传相关的工作流文件到相关的项目中。其中如果是文件采用方式如下,将图片和或者文件转换为二进制字节流存储。
存储的表结构如下:
create table ACT_GE_BYTEARRAY (

??? ID_ varchar(64) not null,

??? REV_ integer,

??? NAME_ varchar(255),

??? DEPLOYMENT_ID_ varchar(64),

??? BYTES_ BLOB,

??? primary key (ID_)

);

其中NAME_存储文件名称。
??? BYTES_存储流程资源文件。
代码实现如下:
package org.activiti.engine.identity;

?

import java.io.ByteArrayInputStream;

import java.io.InputStream;

?

?

/**

?* @author Tom Baeyens

?*/

public class Picture {

?

? protected byte[] bytes;

? protected String mimeType;

?

? public Picture(byte[] bytes, String mimeType) {

??? this.bytes = bytes;

??? this.mimeType = mimeType;

? }

?

? public byte[] getBytes() {

??? return bytes;

? }

?

? public InputStream getInputStream() {

? ??return new ByteArrayInputStream(bytes);

? }

?

? public String getMimeType() {

??? return mimeType;

? }

}

package org.activiti.rest.api.identity;

?

import org.activiti.engine.ActivitiException;

import org.activiti.engine.identity.Picture;

import org.activiti.rest.api.ActivitiUtil;

import org.activiti.rest.api.SecuredResource;

import org.restlet.data.CacheDirective;

import org.restlet.data.MediaType;

import org.restlet.representation.InputRepresentation;

import org.restlet.resource.Get;

?

/**

?* @author Tijs Rademakers

?*/

public class UserPictureResource extends SecuredResource {

?

? @Get

? public InputRepresentation getPicture() {

??? if(authenticate() == false) return null;

???

??? String userId = (String) getRequest().getAttributes().get("userId");

??? if(userId == null) {

????? throw new ActivitiException("No userId provided");

??? }

??? Picture picture = ActivitiUtil.getIdentityService().getUserPicture(userId);

???

??? String contentType = picture.getMimeType();

??? MediaType mediatType = MediaType.IMAGE_PNG;

??? if(contentType != null) {

????? if(contentType.contains(";")) {

??????? contentType = contentType.substring(0, contentType.indexOf(";"));

????? }

????? mediatType = MediaType.valueOf(contentType);

??? }

??? InputRepresentation output = new InputRepresentation(picture.getInputStream(), mediatType);

??? getResponse().getCacheDirectives().add(CacheDirective.maxAge(28800));

???

??? return output;

? }

?

}

package org.activiti.explorer.util;

?

import java.awt.image.BufferedImage;

?

?

/**

?* @author Joram Barrez

?*/

public class ImageUtil {

?

? protected static final Logger LOGGER = Logger.getLogger(ImageUtil.class.getName());

?

? /**

?? * Resizes the given image (passed as {@link InputStream}.

?? * If the image is smaller then the given maximum width or height, the image

?? * will be proportionally resized.

?? */

? public static InputStream smallify(InputStream imageInputStream, String mimeType, int maxWidth, int maxHeight) {

??? try {

????? BufferedImage image = ImageIO.read(imageInputStream);

?????

???? ?int width = Math.min(image.getWidth(), maxWidth);

????? int height = Math.min(image.getHeight(), maxHeight);

?????

????? Mode mode = Mode.AUTOMATIC;

????? if (image.getHeight() > maxHeight) {

??????? mode = Mode.FIT_TO_HEIGHT;

????? }

?????

????? if (width != image.getWidth() || height != image.getHeight()) {

??????? image = Scalr.resize(image, mode, width, height);

????? }

?????

????? ByteArrayOutputStream bos = new ByteArrayOutputStream();

????? ImageIO.write(image, Constants.MIMETYPE_EXTENSION_MAPPING.get(mimeType), bos);

????? return new ByteArrayInputStream(bos.toByteArray());

??? } catch (IOException e) {

????? LOGGER.log(Level.SEVERE, "Exception while resizing image", e);

????? return null;

??? }

? }

?

}

?

?

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