数据库字段存的是多个用户的ID，取出来是多个用户的姓名

select wm_concat(t.user_name) username  from bos_t_user t where t.user_id in       (with tab as (select '990000000000000001,990000000000000002,990000000000000003' id           from ZL_T_PROJECT          where project_id = 990000000000000005)         select substr(',' || id || ',',                       instr(',' || id || ',', ',', 1, level) + 1,                       instr(',' || id || ',', ',', 1, level + 1) -                       instr(',' || id || ',', ',', 1, level) - 1) newid           from tab         connect by level <= length(',' || id || ',') -                    length(replace(',' || id || ',', ',', '')) - 1        )

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