（100分）JS根据父ID，获取所有子ID问题。

JScript code

var video =[            { id:1, pId:0, name:"Video_Data 1", open:true},            { id:11, pId:1, name:"Video_Data 1-1", open:true},            { id:111, pId:11, name:"Video_Data 1-1-1"},            { id:112, pId:11, name:"Video_Data 1-1-2"},            { id:12, pId:1, name:"Video_Data 1-2", open:true},            { id:121, pId:12, name:"Video_Data 1-2-1"},            { id:122, pId:12, name:"Video_Data 1-2-2"},            { id:2, pId:0, name:"Video_Data 2", checked:true, open:true},            { id:21, pId:2, name:"Video_Data 2-1"},            { id:22, pId:2, name:"Video_Data 2-2", open:true},            { id:221, pId:22, name:"Video_Data 2-2-1", checked:true},            { id:222, pId:22, name:"Video_Data 2-2-2"},            { id:23, pId:2, name:"Video_Data 2-3"}        ];

JScript code

function getSubId(node) {    $.each(video, function(index, currentNode) {        if (currentNode.pId == node.id) {            result.push(currentNode);            getSubId(currentNode);        }    });}
[解决办法]
<script type="text/javascript">
var video =[
           { id:1, pId:0, name:"Video_Data 1", open:true},
           { id:11, pId:1, name:"Video_Data 1-1", open:true},
           { id:111, pId:11, name:"Video_Data 1-1-1"},
           { id:112, pId:11, name:"Video_Data 1-1-2"},
           { id:12, pId:1, name:"Video_Data 1-2", open:true},
           { id:121, pId:12, name:"Video_Data 1-2-1"},
           { id:122, pId:12, name:"Video_Data 1-2-2"},
           { id:2, pId:0, name:"Video_Data 2", checked:true, open:true},
           { id:21, pId:2, name:"Video_Data 2-1"},
           { id:22, pId:2, name:"Video_Data 2-2", open:true},
           { id:221, pId:22, name:"Video_Data 2-2-1", checked:true},
           { id:222, pId:22, name:"Video_Data 2-2-2"},
           { id:23, pId:2, name:"Video_Data 2-3"}
       ];
var test=[];
function getNode(id){
  for(var i=0;i<video.length;i++){
if(video[i]["pId"]==id){
alert(video[i]["id"]);
test.push(video[i]);
getNode(video[i]["id"]);
}
}
}
getNode(1);
for(var i=0;i<test.length;i++){
document.write(test[i]["id"]+"<br/>");
}
</script>
这样试试
[解决办法]
需求有点不清楚
[解决办法]
如果是直接的子节点，那上面已经有答案了，如果要获取所有的子节点，那你就递归吧。
[解决办法]
探讨


如果是直接的子节点，那上面已经有答案了，如果要获取所有的子节点，那你就递归吧。

[解决办法]
我怎么就没看懂楼主的问题呢