问个和java对接用json做接口，json序列化和反序列的问题
客户用java做开发，sojo序列化和反序列化，得到的结果如下："endDt":"2012-02-18 16:33:38.155",

然后我用.net做开发，这样的格式没法反序列化，错误为

<?xml version="1.0" encoding="utf-8" ?>
<string xmlns="http://tempuri.org/">{"code":500,"message":"There was an error deserializing the object of type XFFW.Model.SelectiveExaminationModel. DateTime content '2012-02-18 16:33:38.155' does not start with '\\\/Date(' and end with ')\\\/' as required for JSON.","returnvalue":null}</string>

请问碰到这样的事情怎么解决比较好

[解决办法]

C# code

        /*         * DataContractJsonSerializer在System.Runtime.Serialization.Json命名空间下，         * .NET Framework 3.5包含在System.ServiceModel.Web.dll中，需要添加对其的引用；         * .NET Framework 4在System.Runtime.Serialization中。              */        /// <summary>        /// JSON序列化        /// </summary>        public static string JsonSerializer<T>(T t)        {            DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));            System.IO.MemoryStream ms = new System.IO.MemoryStream();            ser.WriteObject(ms, t);            string jsonString = System.Text.Encoding.UTF8.GetString(ms.ToArray());            ms.Close();            //替换Json的Date字符串            string p = @"\\/Date\((\d+)\+\d+\)\\/";            System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertJsonDateToDateString);            System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);            jsonString = reg.Replace(jsonString, matchEvaluator);            return jsonString;        }        /// <summary>        /// JSON反序列化        /// </summary>        public static T JsonDeserialize<T>(string jsonString)        {            //将"yyyy-MM-dd HH:mm:ss"格式的字符串转为"\/Date(1294499956278+0800)\/"格式            string p = @"\d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}";            System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertDateStringToJsonDate);            System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);            jsonString = reg.Replace(jsonString, matchEvaluator);            DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));            System.IO.MemoryStream ms = new System.IO.MemoryStream(Encoding.UTF8.GetBytes(jsonString));            T obj = (T)ser.ReadObject(ms);            return obj;        }        /// <summary>        /// 将Json序列化的时间由/Date(1294499956278+0800)转为字符串        /// </summary>        private static string ConvertJsonDateToDateString(System.Text.RegularExpressions.Match m)        {            string result = string.Empty;            DateTime dt = new DateTime(1970, 1, 1);            dt = dt.AddMilliseconds(long.Parse(m.Groups[1].Value));            dt = dt.ToLocalTime();            result = dt.ToString("yyyy-MM-dd HH:mm:ss");            return result;        }        /// <summary>        /// 将时间字符串转为Json时间        /// </summary>        private static string ConvertDateStringToJsonDate(System.Text.RegularExpressions.Match m)        {            string result = string.Empty;            DateTime dt = DateTime.Parse(m.Groups[0].Value);            dt = dt.ToUniversalTime();            TimeSpan ts = dt - DateTime.Parse("1970-01-01");            result = string.Format("\\/Date({0}+0800)\\/", ts.TotalMilliseconds);            return result;        }