分隔字符，选出需要的行

SQL code

create table temp_T1(   ID int,   U1 varchar(100),   U2 varchar(100)   )insert into temp_T1 select 1,'AA2,BB3,AA,AA4',''insert into temp_T1 select 2,'DD1,DD2',''insert into temp_T1 select 3,'CC1',''insert into temp_T1 select 4,'EE8,AA',''insert into temp_T1 select 5,'XX',''insert into temp_T1 select 6,'','TT'insert into temp_T1 select 7,'CCCC',''insert into temp_T1 select 8,'','AA'insert into temp_T1 select 9,'BXXX',''select * from temp_T1ID          U1                                                                                                   U2----------- ---------------------------------------------------------------- ----------------------------------------------------------------1           AA2,BB3,AA,AA4                                                                                       2           DD1,DD2                                                                                              3           CC1                                                                                                  4           EE8,AA                                                                                               5           XX                                                                                                   6                                                                                                                TT7           CCCC                                                                                                 8                                                                                                                AA9           BXXX                                                                                                 (9 行受影响)

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找出U1栏中有AA的或者U2栏中没有AA的行。请问如何写这个SQL语句比较好呢？



[解决办法]
','+U1+',' LIKE '%,AA,%'
[解决办法]

SQL code

--漏写分隔符select *from tbwhere ','+u1+',' like '%,AA,%' or ','+u2+',' not like '%,AA,%'