怎么遍历出集合里面的 数字啊？

Java code

    public List<Map<String, Object>> findMovieByRegion(String region){                    List<Map<String, Object>> movieList = new ArrayList<Map<String, Object>>();              SQLiteDatabase db = dbHelper.getReadableDatabase();              Cursor cursor = db.rawQuery("select num from Online_movie where region=?", new String[]{region});              while(cursor.moveToNext()){                                    int aa = cursor.getInt(cursor.getColumnIndex("num"));                  HashMap<String, Object> map = new HashMap<String, Object>();                  map.put("aaa", aa);                  System.out.println(map);                  movieList.add(map);              }              return movieList;          }            //______________________________________________      下面是 遍历上面 数据库中的 集合      MovieService ms = new MovieService(this.getBaseContext());                            List<Map<String,Object>> typenum =  ms.findMovieByRegion("美国");                            for (Iterator<Map<String, Object>> typeiterator = typenum.iterator(); typeiterator.hasNext();) {                                    Object num = typeiterator.next();      //这里打印的 num 是{aaa=10},{aaa=9},{aaa=3}可是 我只想得到  10,9,3这几个数字 因为 有花括号的话 组成的路径就是错误的                    Log.v("num===ggggggggggggggg>", ""+num);                                    listmap = FileList.findFile(Environment.getExternalStorageDirectory()+"/Pictures/"+num+".jpg");                                }  

[解决办法]
每个Map里面只有一个键值对是吗？如果是的话就这样
for (Iterator<Map<String, Object>> typeiterator = typenum.iterator(); typeiterator.hasNext();) {
Map<String,Object> map=(HashMap<String,Object>)typeiterator.next();
Log.v("num===ggggggggggggggg>", map.values().get(0)+"");

listmap = FileList.findFile(Environment.getExternalStorageDirectory()+"/Pictures/"+map.values().get(0)+".jpg");

}