怎么样设计一个在1到10中的计数器，当数为1时值为一，以此类推

PHP code

$num = array(    1 => '一',    2 => '二',    3 => '三',    4 => '四',    5 => '五',    6 => '六',    7 => '七',    8 => '八',    9 => '九',);

这是一段php代码，C#类似的思路应该是怎么样呢？

[解决办法]
你可以定义个字典类型

C# code

            Dictionary<int, string> dic = new Dictionary<int, string>();            dic.Add(1, "一");            dic.Add(2, "二");            dic.Add(3, "三");            dic.Add(4, "四");            dic.Add(5, "五");            dic.Add(6, "六");            dic.Add(7, "七");            dic.Add(8, "八");            dic.Add(9, "九");            dic.Add(10, "十");通过dic.TryGetValue 根据key值得到大写的数字
[解决办法]
C# code
string s = @"    1 => '一',    2 => '二',    3 => '三',    4 => '四',    5 => '五',    6 => '六',    7 => '七',    8 => '八',    9 => '九',";int n = 3;string result = s.Substring(s.Select((x, i) => new { x, i }).Where(x => x.x - '0' == n).First().i + 6, 1);
[解决办法]
C# code
 .net 3.5 private static string[] meta = new string[] {"一", "二","三","四","五","六","七","八","九","十"};        public static string Getxxxxxxxx(this int xI,int i)        {          if(Enumerable.Range(0,10).Contains(i))          {              return meta[i];          }            return string.Empty;        }