可变参数输出问题
要从一个二进制文件中读出数据，然后根据一个表里的打印格式化字符串，将数据打印出来；
例如：格式化控制字符串存储如下

NO.Format
1message：%s
2num：%d, id=%d
3address：%lx, message：%s, message：%s
4string：%s, number：%d
5number：%d, string：%s, message：%s
函数接口如下：

C/C++ code

void FormatMessage(int id, LPBYTE lpdata){    //根据id的值，来确定format        //例如：如果id=2， 则lpdata按照"%d, %d"的格式输出}

怎么实现？大家有什么好的建议，谢谢

[解决办法]
分类讨论，高中数学的重点考点。
[解决办法]
switch语句不好吗
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switch(id)简单明了啊。
[解决办法]
const char* formats[] = {"%s", "%d %d", ..........};
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仅供参考

C/C++ code

#include <stdio.h>#include <stdlib.h>#include <string.h>#ifdef WIN32    #include <windows.h>    #include <io.h>#else    #include <unistd.h>    #include <sys/time.h>    #include <pthread.h>    #define  CRITICAL_SECTION   pthread_mutex_t    #define  _vsnprintf         vsnprintf#endif//Log{#define MAXLOGSIZE 20000000#define ARRSIZE(x) (sizeof(x)/sizeof(x[0]))#include <time.h>#include <sys/timeb.h>#include <stdarg.h>char logfilename1[]="MyLog1.log";char logfilename2[]="MyLog2.log";char logstr[16000];char datestr[16];char timestr[16];char mss[4];CRITICAL_SECTION cs_log;FILE *flog;#ifdef WIN32void Lock(CRITICAL_SECTION *l) {    EnterCriticalSection(l);}void Unlock(CRITICAL_SECTION *l) {    LeaveCriticalSection(l);}#elsevoid Lock(CRITICAL_SECTION *l) {    pthread_mutex_lock(l);}void Unlock(CRITICAL_SECTION *l) {    pthread_mutex_unlock(l);}#endifvoid LogV(const char *pszFmt,va_list argp) {    struct tm *now;    struct timeb tb;    if (NULL==pszFmt||0==pszFmt[0]) return;    if (-1==_vsnprintf(logstr,ARRSIZE(logstr),pszFmt,argp)) logstr[ARRSIZE(logstr)-1]=0;    ftime(&tb);    now=localtime(&tb.time);    sprintf(datestr,"%04d-%02d-%02d",now->tm_year+1900,now->tm_mon+1,now->tm_mday);    sprintf(timestr,"%02d:%02d:%02d",now->tm_hour     ,now->tm_min  ,now->tm_sec );    sprintf(mss,"%03d",tb.millitm);    printf("%s %s.%s %s",datestr,timestr,mss,logstr);    flog=fopen(logfilename1,"a");    if (NULL!=flog) {        fprintf(flog,"%s %s.%s %s",datestr,timestr,mss,logstr);        if (ftell(flog)>MAXLOGSIZE) {            fclose(flog);            if (rename(logfilename1,logfilename2)) {                remove(logfilename2);                rename(logfilename1,logfilename2);            }            flog=fopen(logfilename1,"a");            if (NULL==flog) return;        }        fclose(flog);    }}void Log(const char *pszFmt,...) {    va_list argp;    Lock(&cs_log);    va_start(argp,pszFmt);    LogV(pszFmt,argp);    va_end(argp);    Unlock(&cs_log);}//Log}int main(int argc,char * argv[]) {    int i;#ifdef WIN32    InitializeCriticalSection(&cs_log);#else    pthread_mutex_init(&cs_log,NULL);#endif    for (i=0;i<10000;i++) {        Log("This is a Log %04d from FILE:%s LINE:%d\n",i, __FILE__, __LINE__);    }#ifdef WIN32    DeleteCriticalSection(&cs_log);#else    pthread_mutex_destroy(&cs_log);#endif    return 0;}
[解决办法]
探讨


引用:
const char* formats[] = {"%s", "%d %d", ..........}; 
 


可能是我没说清楚吧
数据量非常大，并且表里的数据项也有上万项；
每次都要去查表

这种方式不可行吧

[解决办法]
感觉可以用模板来坐

C/C++ code
class PrintBase{public:    virtual void Print() = 0;protected:private:};template<typename _1>class PrintWithPara1 : public PrintBase{public:    PrintWithPara1(std::string format,_1 para1) : _format(format), _para1(para1)    {    }    void Print()    {        printf(_format.c_str(),_para1);    }protected:private:    std::string _format;    _1 _para1;};    std::map<int ,PrintBase *> print_map;            std::map<int ,PrintBase *>::iterator it = print_map.find(0);    it->second->Print();
[解决办法]
探讨

引用:

仅供参考C/C++ code
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#ifdef WIN32
#include <windows.h>
#include <io.h>
#else
#include <unistd.h>
#include <sys/time.h>
#in……