android java 获得root权限后,执行adb shell命令的问题
android java 成功获得root权限后(log信息可知), 执行adb shell命令时, 出错, 是什么地方的问题呢?


Runtime ex = Runtime.getRuntime();
String cmdBecomeSu = "su";
String script = "busybox chmod a+rw /dev/input/event1";
String script1 = "busybox sendevent /dev/input/event1 1 116 1";
String script2 = "busybox sendevent /dev/input/event1 0 0 0";
String script3 = "busybox sendevent /dev/input/event1 1 116 0";
String script4 = "busybox sendevent /dev/input/event1 0 0 0";

try{
java.lang.Process runsum = ex.exec(cmdBecomeSu);
int exitVal = 0;
final OutputStreamWriter out = new OutputStreamWriter(runsum.getOutputStream());

// Write the script to be executed
out.write(script);

// Ensure that the last character is an "enter"
out.write("\n");
out.flush();

// Terminate the "su" process
out.write("exit\n");
out.flush();

exitVal = runsum.waitFor();
if (exitVal == 0) {
Log.e("Debug", "...Successfully to su");
}

//*********************************************
out.write(script1);

// Ensure that the last character is an "enter"
out.write("\n");
out.flush();

// Terminate the "su" process
out.write("exit\n");
out.flush();
//*********************************************

//*********************************************
out.write(script2);

// Ensure that the last character is an "enter"
out.write("\n");
out.flush();

// Terminate the "su" process
out.write("exit\n");
out.flush();
//*********************************************

//*********************************************
out.write(script3);

// Ensure that the last character is an "enter"
out.write("\n");
out.flush();

// Terminate the "su" process
out.write("exit\n");
out.flush();
//*********************************************

//*********************************************
out.write(script4);

// Ensure that the last character is an "enter"
out.write("\n");
out.flush();

// Terminate the "su" process
out.write("exit\n");
out.flush();
//*********************************************



} catch ( Exception e){
Log.e("Debug", "Fails to su");
}


[解决办法]
在
Log.e("Debug", "Fails to su");
前面加上
e.printStackTrace();

看一下具体出错提示
[解决办法]