如何jquery each()方法遍历组成新的数组
通过jquery的$.each（）方法遍历一个对象并取其ID重新拼装成一个数组如何操作？
比如遍历select对象，并取其值：
<select id="test1">
<option>1</option>
<option>2</option>
<option>3</option>
<option>4</option>
</select>
然后拼装成{1,2,3,4}这样的数组，或者json对象
[解决办法]
- HTML code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script><script type="text/javascript">var glob_oplist = new Array();$(document).ready(function() {$('#test1').each( function() { $(this).children("option").each( function() { glob_oplist.push($(this).text()) } ) } ) alert(JSON.stringify(glob_oplist))})</script></head><body><select id="test1"> <option>1</option> <option>2</option> <option>3</option><option>4</option></select></body></html>
[解决办法]
- HTML code
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.js"></script> <script>$(document).ready(function(){ var ar=new Array(); $("#test1").children("option").each(function(){ ar.push($(this).text()); }); alert(ar);});</script><select id="test1"> <option>1</option> <option>2</option> <option>3</option> <option>4</option></select>