json递归问题
var nodes = [
{ "id": 2, "title": "江苏", "parentid": 0 },
{ "id": 3, "title": "无锡", "parentid": 2 },
{ "id": 4, "title": "常州", "parentid": 2 },
{ "id": 5, "title": "金坛", "parentid": 4 },
{ "id": 6, "title": "宜兴", "parentid": 3 }，
{ "id": 7, "title": "温州", "parentid": 9 }，
{ "id": 8, "title": "杭州", "parentid": 9 }，
{ "id": 9, "title": "浙江", "parentid": 0}
]

以上格式数据N条，我想获得id=2 即江苏下面所有地区，包括地级市及下属区县格式数据，结果如下：
{ "id": 2, "title": "江苏", "parentid": 0 },
{ "id": 3, "title": "无锡", "parentid": 2 },
{ "id": 4, "title": "常州", "parentid": 2 },
{ "id": 5, "title": "金坛", "parentid": 4 },
{ "id": 6, "title": "宜兴", "parentid": 3 }，

请问用js或者jquery怎么获取以上数据

[解决办法]

JScript code

var nodes = [{ "id": 2, "title": "江苏", "parentid": 0 },{ "id": 3, "title": "无锡", "parentid": 2 },{ "id": 4, "title": "常州", "parentid": 2 },{ "id": 5, "title": "金坛", "parentid": 4 },{ "id": 6, "title": "宜兴", "parentid": 3 },{ "id": 7, "title": "温州", "parentid": 9 },{ "id": 8, "title": "杭州", "parentid": 9 },{ "id": 9, "title": "浙江", "parentid": 0}];var Node=function(obj){    for(var p in obj)this[p]=obj[p];    this._children=[];};Node.prototype={    _addChild:function(node){        this._children.push(node);    },    _getRaw:function(){        var o={};        for(var p in this)if(this.hasOwnProperty(p) && p!='_children')o[p]=this[p];        return o;    }};var Map=function(){    this._keys=[];};Map.prototype={    _containsKey:function(k){        if(this.hasOwnProperty(k))return true;        return false;    },    _put:function(k,v){if(!this._containsKey(k))this._keys.push(k);this[k]=v},    _get:function(k){return this[k];}};var ns=new Map(),root,n,ids;for(var i=nodes.length-1;i>=0;i--){    n=new Node(nodes[i]);    ns._put(n.id,n);    if(n.id==2)root=n;}ids=ns._keys;for(var i=ids.length-1;i>=0;i--){    n=ns._get(ids[i]);    if(!n)continue;    if(ns._containsKey(n.parentid))ns._get(n.parentid)._addChild(n);}//经过上面的处理，root是一个树的根节点，root本身是id=2的那个记录，如果要获取所有的记录而不是树，请继续：ns=[];var getAll=function(node){    ns.push(node._getRaw());    for(var cs=node._children,i=0,il=cs.length;i<il;i++)getAll(cs[i])}getAll(root);//到此ns为所有符合要求的记录集for(var i=0,il=ns.length;i<il;i++)alert(ns[i].id)
[解决办法]
var nodes = [
{ "id": 2, "title": "江苏", "parentid": 0 },
{ "id": 3, "title": "无锡", "parentid": 2 },
{ "id": 4, "title": "常州", "parentid": 2 },
{ "id": 5, "title": "金坛", "parentid": 4 },
{ "id": 6, "title": "宜兴", "parentid": 3 },
{ "id": 7, "title": "温州", "parentid": 9 },
{ "id": 8, "title": "杭州", "parentid": 9 },
{ "id": 9, "title": "浙江", "parentid": 0} 
 
]
var node=[];
function getNode(id){
for(var i=0;i<nodes.length;i++){
if(nodes[i]["id"]==id){
node.push(nodes[i]);
}
if(nodes[i]["parentid"]==id){
getNode(nodes[i]["id"]);
}
}
}  
getNode(2);
for(var i=0;i<node.length;i++){
document.write(node[i]["id"]);
}
</script>
这样试试