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Oracle中INSTR跟SUBSTR的用法

发布时间: 2012-08-21 13:00:21 作者: rapoo

Oracle中INSTR和SUBSTR的用法

Oracle中INSTR的用法:
INSTR方法的格式为
INSTR(源字符串, 要查找的字符串, 从第几个字符开始, 要找到第几个匹配的序号)
返回找到的位置,如果找不到则返回0.
例如:INSTR('CORPORATE FLOOR','OR', 3, 2)中,源字符串为'CORPORATE FLOOR', 在字符串中查找'OR',从第三个字符位置开始查找"OR",取第三个字后第2个匹配项的位置。

默认查找顺序为从左到右。当起始位置为负数的时候,从右边开始查找。

所以SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "aaa" FROM DUAL的显示结果是

Instring
——————
14


oracle的substr函数的用法:
?取得字符串中指定起始位置和长度的字符串?? substr( string, start_position, [ length ] )
?如:
???? substr('This is a test', 6, 2)???? would return 'is'
???? substr('This is a test', 6)???? would return 'is a test'
???? substr('TechOnTheNet', -3, 3)???? would return 'Net'
???? substr('TechOnTheNet', -6, 3)???? would return 'The'
?
select substr('Thisisatest', -4, 2) value from dual


综合应用:
SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "Instring" FROM DUAL
--INSTR(源字符串, 目标字符串, 起始位置, 匹配序号)
SELECT INSTR('CORPORATE FLOOR','OR', 3, 2) "Instring" FROM DUAL

SELECT INSTR('32.8,63.5',',', 1, 1) "Instring" FROM DUAL

SELECT SUBSTR('32.8,63.5',INSTR('32.8,63.5',',', 1, 1)+1) "INSTRING" FROM DUAL
SELECT SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',', 1, 1)-1) "INSTRING" FROM DUAL

-- CREATED ON 2008-9-26 BY ADMINISTRATOR DECLARE  -- LOCAL VARIABLES HERE  T   VARCHAR2(2000);  S   VARCHAR2(2000);  NUM INTEGER;  I   INTEGER;  POS INTEGER;BEGIN  -- TEST STATEMENTS HERE  T := '12.3,23.0;45.6,54.2;32.8,63.5;';  SELECT LENGTH(T) - LENGTH(REPLACE(T, ';', '')) INTO NUM FROM DUAL;  DBMS_OUTPUT.PUT_LINE('NUM:' || NUM);  POS := 0;  FOR I IN 1 .. NUM LOOP    DBMS_OUTPUT.PUT_LINE('I:' || I);    DBMS_OUTPUT.PUT_LINE('POS:' || POS);    DBMS_OUTPUT.PUT_LINE('==:' || INSTR(T, ';', 1, I));    DBMS_OUTPUT.PUT_LINE('INSTR:' || SUBSTR(T, POS + 1, INSTR(T, ';', 1, I) - 1));    POS := INSTR(T, ';', 1, I);  END LOOP;END;-- Created on 2008-9-26 by ADMINISTRATOR declare   -- Local variables here  i integer;  T      VARCHAR2(2000);  S      VARCHAR2(2000);begin  -- Test statements here    --历史状态  T := '12.3,23.0;45.6,54.2;32.8,63.5;';  IF (T IS NOT NULL) AND (LENGTH(T) > 0) THEN    --T := T || ',';    WHILE LENGTH(T) > 0 LOOP      --ISTATUSID := 0;      S         := TRIM(SUBSTR(T, 1, INSTR(T, ';') - 1));      IF LENGTH(S) > 0 THEN         DBMS_OUTPUT.PUT_LINE('LAT:'||SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',', 1, 1)-1));         DBMS_OUTPUT.PUT_LINE('LON:'||SUBSTR('32.8,63.5',INSTR('32.8,63.5',',', 1, 1)+1));/*        INSERT INTO T_HISTORY_RESPONSESTATUS          (HISTORYID, RESPONSESTATUSID, STAMP, CALL_LETTER)        VALUES          (IHISTORYID, S, ISTAMP, ICALL_LETTER);*/        -- COMMIT;      END IF;      T := SUBSTR(T, INSTR(T, ';') + 1);    END LOOP;  END IF;  end;

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本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/E_wsq/archive/2008/09/26/2983102.aspx

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