闲着没事 Burlap开发学习 总结
?????? 前面总结关于Hessian的开发WebService的方法,在Caucho公司开发的有两种实现远程访问调用方式:Hessian和Burlap。
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Burlap 简介
Burlap也是有caucho提供,它和hessian的不同在于,它是基于XML-RPC协议的。
1、是基于什么协议实现的?
基于XML-RPC协议实现。
2、怎么发起请求?
根据Burlap提供的API。
3、怎么将请求转化为符合协议的格式的?
将请求信息转化为符合协议的XML格式,转化为流进行传输。
4、使用什么传输协议传输?
Http协议。
5、响应端基于什么机制来接收请求?
监听Http请求。
6、怎么将流还原为传输格式的?
根据XML-RPC协议进行还原。
7、处理完毕后怎么回应?
返回结果写入XML中,由Burlap返回至调用端。
声明服务端接口:
package com.easyway.caucho.burlap.ws;import java.util.List;/** * 声明服务端相关的服务 * @author longgangbai * */public interface IBurlapService {public String getUserName();public List<String> getList();public void setGreeting(String greeting);public String hello();}?
实现服务端的服务代码示例如下:
package com.easyway.caucho.burlap.ws;import java.util.ArrayList;import java.util.List;import com.caucho.burlap.server.BurlapServlet;/** * * 在Burlap中服务端的必须继承BurlapServlet 类同时实现相关的服务的接口 * * @author longgangbai * */public class BurlapWS extends BurlapServlet implements IBurlapService{private String _greeting = "Hello, world";/** * */ public void setGreeting(String greeting) { _greeting = greeting; }/** * */ public String hello() { return _greeting; } /** * */public List<String> getList() { List<String> strList=new ArrayList<String>(); strList.add("a"); strList.add("c"); strList.add("b"); strList.add("d"); strList.add("e"); strList.add("g"); strList.add("h"); strList.add("j"); strList.add("k"); strList.add("l"); strList.add("q");return strList;}/** * */public String getUserName() {return _greeting;}}?
客户端访问代码如下:
package com.easyway.caucho.burlap.ws;import java.net.MalformedURLException;import com.caucho.burlap.client.BurlapProxyFactory;/** * Burlap客户端测试代码 * @author longgangbai * */public class BurlapServiceWSClient {public static void main(String[] args) {String url = "http://localhost:8080/BurlapWS/remoting/burlapWs";BurlapProxyFactory factory = new BurlapProxyFactory();IBurlapService basic;try {basic = (IBurlapService) factory.create(IBurlapService.class, url);System.out.println("hello(): " + basic.getUserName());System.out.println("getList(): " + basic.getUserName());} catch (MalformedURLException e) {// TODO Auto-generated catch blocke.printStackTrace();}}}?
web.xml配置如下:
<?xml version="1.0" encoding="UTF-8"?><web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"><servlet> <servlet-name>burlapWs</servlet-name> <servlet-class>com.easyway.caucho.burlap.ws.BurlapWS</servlet-class></servlet><servlet-mapping> <servlet-name>burlapWs</servlet-name> <url-pattern>/remoting/burlapWs</url-pattern></servlet-mapping> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list></web-app>
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