nyoj 可以直接写的简单题

Triangular Sums nyoj 122

#include<iostream>using namespace std;int main(){    int N, score;    cin>>N;    while(N--)    {              cin>>score;              if(score >= 90  &&  score <= 100)                       cout<<"A"<<endl;              else if(score >= 80  &&  score <= 89)                       cout<<"B"<<endl;               else if(score >= 70  &&  score <= 79)                       cout<<"C"<<endl;              else if(score >= 60  &&  score <= 69)                       cout<<"D"<<endl;              else if(score >= 0  &&  score <= 59)                       cout<<"E"<<endl;                         }    return 0;}