编译通不过,那个地方错了呢? const后置为啥

编译通不过,那个地方错了呢? const后置为什么？

C/C++ code

#include &lt;iostream&gt;class point{public:        point(float x=0,float y=0);        void setPoint(float,float);        float getX() const {return x;}        float getY() const {return y;}        friend ostream & operator&lt;&lt;(ostream &,const point &);protected:          float x,y;          };point::point(float a,float b)          {x=a;y=b;}point::void setPoint(float a,float b)          {x=a;y=b;}point::ostream & operator&lt;&lt;(ostream &output,const point &p)          {output&lt;&lt;"["&lt;&lt;p.x&lt;&lt;","&lt;&lt;p.y&lt;&lt;"]"&lt;&lt;endl;          return output;}          int main(){Point p(3.5,6.4);cout&lt;&lt;"x="&lt;&lt;p.getX()&lt;&lt;",y="&lt;&lt;p.getY()&lt;&lt;endl;p.setPoint(8.5,6.8);cout&lt;&lt;"p(new):"&lt;&lt;p&lt;&lt;endl;}

[解决办法]
简单改了一下，只是改成能编译通过运行了，没看逻辑

C/C++ code

#include &lt;iostream&gt;using namespace std;class point{public:point(float x=0,float y=0);void setPoint(float,float);float getX() const {return x;}float getY() const {return y;}friend ostream & operator&lt;&lt;(ostream &,const point &);protected:    float x,y;};point::point(float a,float b){x=a;y=b;}void point::setPoint(float a,float b){x=a;y=b;}ostream & operator&lt;&lt;(ostream &output,const point &p){output&lt;&lt;"["&lt;&lt;p.x&lt;&lt;","&lt;&lt;p.y&lt;&lt;"]"&lt;&lt;endl;return output;}int main(){point p(3.5,6.4);cout&lt;&lt;"x="&lt;&lt;p.getX()&lt;&lt;",y="&lt;&lt;p.getY()&lt;&lt;endl;p.setPoint(8.5,6.8);cout&lt;&lt;"p(new):"&lt;&lt;p&lt;&lt;endl;}
[解决办法]
float getX() const {return x;}
&gt;&gt;const后置表明该函数不修改类成员

编译通不过,那个地方错了呢? const后置

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